Metamath Proof Explorer


Theorem relogbdiv

Description: The logarithm of the quotient of two positive real numbers is the difference of logarithms. Property 3 of Cohen4 p. 361. (Contributed by AV, 29-May-2020)

Ref Expression
Assertion relogbdiv ⊢ B ∈ ℂ ∖ 0 1 ∧ A ∈ ℝ + ∧ C ∈ ℝ + → log B A C = log B A − log B C

Proof

Step Hyp Ref Expression
1 neg1rr ⊢ − 1 ∈ ℝ
2 relogbmulexp ⊢ B ∈ ℂ ∖ 0 1 ∧ A ∈ ℝ + ∧ C ∈ ℝ + ∧ − 1 ∈ ℝ → log B A ⁢ C − 1 = log B A + -1 ⁢ log B C
3 1 2 mp3anr3 ⊢ B ∈ ℂ ∖ 0 1 ∧ A ∈ ℝ + ∧ C ∈ ℝ + → log B A ⁢ C − 1 = log B A + -1 ⁢ log B C
4 rpcn ⊢ A ∈ ℝ + → A ∈ ℂ
5 4 adantr ⊢ A ∈ ℝ + ∧ C ∈ ℝ + → A ∈ ℂ
6 rpcn ⊢ C ∈ ℝ + → C ∈ ℂ
7 6 adantl ⊢ A ∈ ℝ + ∧ C ∈ ℝ + → C ∈ ℂ
8 rpne0 ⊢ C ∈ ℝ + → C ≠ 0
9 8 adantl ⊢ A ∈ ℝ + ∧ C ∈ ℝ + → C ≠ 0
10 5 7 9 divrecd ⊢ A ∈ ℝ + ∧ C ∈ ℝ + → A C = A ⁢ 1 C
11 1cnd ⊢ C ∈ ℝ + → 1 ∈ ℂ
12 6 8 11 cxpnegd ⊢ C ∈ ℝ + → C − 1 = 1 C 1
13 6 cxp1d ⊢ C ∈ ℝ + → C 1 = C
14 13 oveq2d ⊢ C ∈ ℝ + → 1 C 1 = 1 C
15 12 14 eqtrd ⊢ C ∈ ℝ + → C − 1 = 1 C
16 15 adantl ⊢ A ∈ ℝ + ∧ C ∈ ℝ + → C − 1 = 1 C
17 16 oveq2d ⊢ A ∈ ℝ + ∧ C ∈ ℝ + → A ⁢ C − 1 = A ⁢ 1 C
18 10 17 eqtr4d ⊢ A ∈ ℝ + ∧ C ∈ ℝ + → A C = A ⁢ C − 1
19 18 adantl ⊢ B ∈ ℂ ∖ 0 1 ∧ A ∈ ℝ + ∧ C ∈ ℝ + → A C = A ⁢ C − 1
20 19 oveq2d ⊢ B ∈ ℂ ∖ 0 1 ∧ A ∈ ℝ + ∧ C ∈ ℝ + → log B A C = log B A ⁢ C − 1
21 rpcndif0 ⊢ C ∈ ℝ + → C ∈ ℂ ∖ 0
22 21 adantl ⊢ A ∈ ℝ + ∧ C ∈ ℝ + → C ∈ ℂ ∖ 0
23 logbcl ⊢ B ∈ ℂ ∖ 0 1 ∧ C ∈ ℂ ∖ 0 → log B C ∈ ℂ
24 22 23 sylan2 ⊢ B ∈ ℂ ∖ 0 1 ∧ A ∈ ℝ + ∧ C ∈ ℝ + → log B C ∈ ℂ
25 mulm1 ⊢ log B C ∈ ℂ → -1 ⁢ log B C = − log B C
26 25 oveq2d ⊢ log B C ∈ ℂ → log B A + -1 ⁢ log B C = log B A + − log B C
27 24 26 syl ⊢ B ∈ ℂ ∖ 0 1 ∧ A ∈ ℝ + ∧ C ∈ ℝ + → log B A + -1 ⁢ log B C = log B A + − log B C
28 rpcndif0 ⊢ A ∈ ℝ + → A ∈ ℂ ∖ 0
29 28 adantr ⊢ A ∈ ℝ + ∧ C ∈ ℝ + → A ∈ ℂ ∖ 0
30 logbcl ⊢ B ∈ ℂ ∖ 0 1 ∧ A ∈ ℂ ∖ 0 → log B A ∈ ℂ
31 29 30 sylan2 ⊢ B ∈ ℂ ∖ 0 1 ∧ A ∈ ℝ + ∧ C ∈ ℝ + → log B A ∈ ℂ
32 31 24 negsubd ⊢ B ∈ ℂ ∖ 0 1 ∧ A ∈ ℝ + ∧ C ∈ ℝ + → log B A + − log B C = log B A − log B C
33 27 32 eqtr2d ⊢ B ∈ ℂ ∖ 0 1 ∧ A ∈ ℝ + ∧ C ∈ ℝ + → log B A − log B C = log B A + -1 ⁢ log B C
34 3 20 33 3eqtr4d ⊢ B ∈ ℂ ∖ 0 1 ∧ A ∈ ℝ + ∧ C ∈ ℝ + → log B A C = log B A − log B C