Metamath Proof Explorer


Theorem relss

Description: Subclass theorem for relation predicate. Theorem 2 of Suppes p. 58. (Contributed by NM, 15-Aug-1994)

Ref Expression
Assertion relss A B Rel B Rel A

Proof

Step Hyp Ref Expression
1 sstr2 A B B V × V A V × V
2 df-rel Rel B B V × V
3 df-rel Rel A A V × V
4 1 2 3 3imtr4g A B Rel B Rel A