Metamath Proof Explorer


Theorem resfval2

Description: Value of the functor restriction operator. (Contributed by Mario Carneiro, 6-Jan-2017)

Ref Expression
Hypotheses resfval.c ⊢ φ → F ∈ V
resfval.d ⊢ φ → H ∈ W
resfval2.g ⊢ φ → G ∈ X
resfval2.d ⊢ φ → H Fn S × S
Assertion resfval2 ⊢ φ → F G ↾ f H = F ↾ S x ∈ S , y ∈ S ⟼ x G y ↾ x H y

Proof

Step Hyp Ref Expression
1 resfval.c ⊢ φ → F ∈ V
2 resfval.d ⊢ φ → H ∈ W
3 resfval2.g ⊢ φ → G ∈ X
4 resfval2.d ⊢ φ → H Fn S × S
5 opex ⊢ F G ∈ V
6 5 a1i ⊢ φ → F G ∈ V
7 6 2 resfval ⊢ φ → F G ↾ f H = 1 st ⁡ F G ↾ dom ⁡ dom ⁡ H z ∈ dom ⁡ H ⟼ 2 nd ⁡ F G ⁡ z ↾ H ⁡ z
8 op1stg ⊢ F ∈ V ∧ G ∈ X → 1 st ⁡ F G = F
9 1 3 8 syl2anc ⊢ φ → 1 st ⁡ F G = F
10 4 fndmd ⊢ φ → dom ⁡ H = S × S
11 10 dmeqd ⊢ φ → dom ⁡ dom ⁡ H = dom ⁡ S × S
12 dmxpid ⊢ dom ⁡ S × S = S
13 11 12 eqtrdi ⊢ φ → dom ⁡ dom ⁡ H = S
14 9 13 reseq12d ⊢ φ → 1 st ⁡ F G ↾ dom ⁡ dom ⁡ H = F ↾ S
15 op2ndg ⊢ F ∈ V ∧ G ∈ X → 2 nd ⁡ F G = G
16 1 3 15 syl2anc ⊢ φ → 2 nd ⁡ F G = G
17 16 fveq1d ⊢ φ → 2 nd ⁡ F G ⁡ z = G ⁡ z
18 17 reseq1d ⊢ φ → 2 nd ⁡ F G ⁡ z ↾ H ⁡ z = G ⁡ z ↾ H ⁡ z
19 10 18 mpteq12dv ⊢ φ → z ∈ dom ⁡ H ⟼ 2 nd ⁡ F G ⁡ z ↾ H ⁡ z = z ∈ S × S ⟼ G ⁡ z ↾ H ⁡ z
20 fveq2 ⊢ z = x y → G ⁡ z = G ⁡ x y
21 df-ov ⊢ x G y = G ⁡ x y
22 20 21 eqtr4di ⊢ z = x y → G ⁡ z = x G y
23 fveq2 ⊢ z = x y → H ⁡ z = H ⁡ x y
24 df-ov ⊢ x H y = H ⁡ x y
25 23 24 eqtr4di ⊢ z = x y → H ⁡ z = x H y
26 22 25 reseq12d ⊢ z = x y → G ⁡ z ↾ H ⁡ z = x G y ↾ x H y
27 26 mpompt ⊢ z ∈ S × S ⟼ G ⁡ z ↾ H ⁡ z = x ∈ S , y ∈ S ⟼ x G y ↾ x H y
28 19 27 eqtrdi ⊢ φ → z ∈ dom ⁡ H ⟼ 2 nd ⁡ F G ⁡ z ↾ H ⁡ z = x ∈ S , y ∈ S ⟼ x G y ↾ x H y
29 14 28 opeq12d ⊢ φ → 1 st ⁡ F G ↾ dom ⁡ dom ⁡ H z ∈ dom ⁡ H ⟼ 2 nd ⁡ F G ⁡ z ↾ H ⁡ z = F ↾ S x ∈ S , y ∈ S ⟼ x G y ↾ x H y
30 7 29 eqtrd ⊢ φ → F G ↾ f H = F ↾ S x ∈ S , y ∈ S ⟼ x G y ↾ x H y