Metamath Proof Explorer


Theorem resindir

Description: Class restriction distributes over intersection. (Contributed by NM, 18-Dec-2008)

Ref Expression
Assertion resindir A B C = A C B C

Proof

Step Hyp Ref Expression
1 inindir A B C × V = A C × V B C × V
2 df-res A B C = A B C × V
3 df-res A C = A C × V
4 df-res B C = B C × V
5 3 4 ineq12i A C B C = A C × V B C × V
6 1 2 5 3eqtr4i A B C = A C B C