Metamath Proof Explorer


Theorem resiun1

Description: Distribution of restriction over indexed union. (Contributed by Mario Carneiro, 29-May-2015) (Proof shortened by JJ, 25-Aug-2021)

Ref Expression
Assertion resiun1 x A B C = x A B C

Proof

Step Hyp Ref Expression
1 iunin1 x A B C × V = x A B C × V
2 df-res B C = B C × V
3 2 a1i x A B C = B C × V
4 3 iuneq2i x A B C = x A B C × V
5 df-res x A B C = x A B C × V
6 1 4 5 3eqtr4ri x A B C = x A B C