Metamath Proof Explorer


Theorem ressmulgnn0d

Description: Values for the group multiple function in a restricted structure. (Contributed by Thierry Arnoux, 14-Jun-2017)

Ref Expression
Hypotheses ressmulgnn0d.1 ⊢ φ → G ↾ 𝑠 A = H
ressmulgnn0d.2 ⊢ φ → 0 G = 0 H
ressmulgnn0d.3 ⊢ φ → A ⊆ Base G
ressmulgnn0d.4 ⊢ φ → N ∈ ℕ 0
ressmulgnn0d.5 ⊢ φ → X ∈ A
Assertion ressmulgnn0d ⊢ φ → N ⋅ H X = N ⋅ G X

Proof

Step Hyp Ref Expression
1 ressmulgnn0d.1 ⊢ φ → G ↾ 𝑠 A = H
2 ressmulgnn0d.2 ⊢ φ → 0 G = 0 H
3 ressmulgnn0d.3 ⊢ φ → A ⊆ Base G
4 ressmulgnn0d.4 ⊢ φ → N ∈ ℕ 0
5 ressmulgnn0d.5 ⊢ φ → X ∈ A
6 1 fveq2d ⊢ φ → ⋅ G ↾ 𝑠 A = ⋅ H
7 6 oveqd ⊢ φ → N ⋅ G ↾ 𝑠 A X = N ⋅ H X
8 7 adantr ⊢ φ ∧ N ∈ ℕ → N ⋅ G ↾ 𝑠 A X = N ⋅ H X
9 eqid ⊢ G ↾ 𝑠 A = G ↾ 𝑠 A
10 3 adantr ⊢ φ ∧ N ∈ ℕ → A ⊆ Base G
11 5 adantr ⊢ φ ∧ N ∈ ℕ → X ∈ A
12 simpr ⊢ φ ∧ N ∈ ℕ → N ∈ ℕ
13 9 10 11 12 ressmulgnnd ⊢ φ ∧ N ∈ ℕ → N ⋅ G ↾ 𝑠 A X = N ⋅ G X
14 8 13 eqtr3d ⊢ φ ∧ N ∈ ℕ → N ⋅ H X = N ⋅ G X
15 5 adantr ⊢ φ ∧ N = 0 → X ∈ A
16 eqid ⊢ Base G = Base G
17 9 16 ressbas2 ⊢ A ⊆ Base G → A = Base G ↾ 𝑠 A
18 3 17 syl ⊢ φ → A = Base G ↾ 𝑠 A
19 18 adantr ⊢ φ ∧ N = 0 → A = Base G ↾ 𝑠 A
20 15 19 eleqtrd ⊢ φ ∧ N = 0 → X ∈ Base G ↾ 𝑠 A
21 eqid ⊢ Base G ↾ 𝑠 A = Base G ↾ 𝑠 A
22 eqid ⊢ 0 G ↾ 𝑠 A = 0 G ↾ 𝑠 A
23 eqid ⊢ ⋅ G ↾ 𝑠 A = ⋅ G ↾ 𝑠 A
24 21 22 23 mulg0 ⊢ X ∈ Base G ↾ 𝑠 A → 0 ⋅ G ↾ 𝑠 A X = 0 G ↾ 𝑠 A
25 20 24 syl ⊢ φ ∧ N = 0 → 0 ⋅ G ↾ 𝑠 A X = 0 G ↾ 𝑠 A
26 6 oveqd ⊢ φ → 0 ⋅ G ↾ 𝑠 A X = 0 ⋅ H X
27 26 adantr ⊢ φ ∧ N = 0 → 0 ⋅ G ↾ 𝑠 A X = 0 ⋅ H X
28 1 adantr ⊢ φ ∧ N = 0 → G ↾ 𝑠 A = H
29 28 fveq2d ⊢ φ ∧ N = 0 → 0 G ↾ 𝑠 A = 0 H
30 2 adantr ⊢ φ ∧ N = 0 → 0 G = 0 H
31 29 30 eqtr4d ⊢ φ ∧ N = 0 → 0 G ↾ 𝑠 A = 0 G
32 25 27 31 3eqtr3d ⊢ φ ∧ N = 0 → 0 ⋅ H X = 0 G
33 simpr ⊢ φ ∧ N = 0 → N = 0
34 33 oveq1d ⊢ φ ∧ N = 0 → N ⋅ H X = 0 ⋅ H X
35 3 adantr ⊢ φ ∧ N = 0 → A ⊆ Base G
36 35 15 sseldd ⊢ φ ∧ N = 0 → X ∈ Base G
37 eqid ⊢ 0 G = 0 G
38 eqid ⊢ ⋅ G = ⋅ G
39 16 37 38 mulg0 ⊢ X ∈ Base G → 0 ⋅ G X = 0 G
40 36 39 syl ⊢ φ ∧ N = 0 → 0 ⋅ G X = 0 G
41 32 34 40 3eqtr4d ⊢ φ ∧ N = 0 → N ⋅ H X = 0 ⋅ G X
42 33 oveq1d ⊢ φ ∧ N = 0 → N ⋅ G X = 0 ⋅ G X
43 41 42 eqtr4d ⊢ φ ∧ N = 0 → N ⋅ H X = N ⋅ G X
44 elnn0 ⊢ N ∈ ℕ 0 ↔ N ∈ ℕ ∨ N = 0
45 4 44 sylib ⊢ φ → N ∈ ℕ ∨ N = 0
46 14 43 45 mpjaodan ⊢ φ → N ⋅ H X = N ⋅ G X