Metamath Proof Explorer


Theorem reusv2lem2

Description: Lemma for reusv2 . (Contributed by NM, 27-Oct-2010) (Proof shortened by Mario Carneiro, 19-Nov-2016) (Proof shortened by JJ, 7-Aug-2021)

Ref Expression
Assertion reusv2lem2 ⊢ ∃! x ∀ y ∈ A x = B → ∃! x ∃ y ∈ A x = B

Proof

Step Hyp Ref Expression
1 eunex ⊢ ∃! x ∀ y ∈ A x = B → ∃ x ¬ ∀ y ∈ A x = B
2 exnal ⊢ ∃ x ¬ ∀ y ∈ A x = B ↔ ¬ ∀ x ∀ y ∈ A x = B
3 1 2 sylib ⊢ ∃! x ∀ y ∈ A x = B → ¬ ∀ x ∀ y ∈ A x = B
4 rzal ⊢ A = ∅ → ∀ y ∈ A x = B
5 4 alrimiv ⊢ A = ∅ → ∀ x ∀ y ∈ A x = B
6 3 5 nsyl3 ⊢ A = ∅ → ¬ ∃! x ∀ y ∈ A x = B
7 6 pm2.21d ⊢ A = ∅ → ∃! x ∀ y ∈ A x = B → ∃! x ∃ y ∈ A x = B
8 simpr ⊢ A ≠ ∅ ∧ ∃! x ∀ y ∈ A x = B → ∃! x ∀ y ∈ A x = B
9 nfra1 ⊢ Ⅎ y ∀ y ∈ A z = B
10 nfra1 ⊢ Ⅎ y ∀ y ∈ A x = B
11 simpr ⊢ ∀ y ∈ A z = B ∧ y ∈ A ∧ x = B → x = B
12 rspa ⊢ ∀ y ∈ A z = B ∧ y ∈ A → z = B
13 12 adantr ⊢ ∀ y ∈ A z = B ∧ y ∈ A ∧ x = B → z = B
14 11 13 eqtr4d ⊢ ∀ y ∈ A z = B ∧ y ∈ A ∧ x = B → x = z
15 eqeq1 ⊢ x = z → x = B ↔ z = B
16 15 ralbidv ⊢ x = z → ∀ y ∈ A x = B ↔ ∀ y ∈ A z = B
17 16 biimprcd ⊢ ∀ y ∈ A z = B → x = z → ∀ y ∈ A x = B
18 17 ad2antrr ⊢ ∀ y ∈ A z = B ∧ y ∈ A ∧ x = B → x = z → ∀ y ∈ A x = B
19 14 18 mpd ⊢ ∀ y ∈ A z = B ∧ y ∈ A ∧ x = B → ∀ y ∈ A x = B
20 19 exp31 ⊢ ∀ y ∈ A z = B → y ∈ A → x = B → ∀ y ∈ A x = B
21 9 10 20 rexlimd ⊢ ∀ y ∈ A z = B → ∃ y ∈ A x = B → ∀ y ∈ A x = B
22 21 adantl ⊢ A ≠ ∅ ∧ ∀ y ∈ A z = B → ∃ y ∈ A x = B → ∀ y ∈ A x = B
23 r19.2z ⊢ A ≠ ∅ ∧ ∀ y ∈ A x = B → ∃ y ∈ A x = B
24 23 ex ⊢ A ≠ ∅ → ∀ y ∈ A x = B → ∃ y ∈ A x = B
25 24 adantr ⊢ A ≠ ∅ ∧ ∀ y ∈ A z = B → ∀ y ∈ A x = B → ∃ y ∈ A x = B
26 22 25 impbid ⊢ A ≠ ∅ ∧ ∀ y ∈ A z = B → ∃ y ∈ A x = B ↔ ∀ y ∈ A x = B
27 26 eubidv ⊢ A ≠ ∅ ∧ ∀ y ∈ A z = B → ∃! x ∃ y ∈ A x = B ↔ ∃! x ∀ y ∈ A x = B
28 27 ex ⊢ A ≠ ∅ → ∀ y ∈ A z = B → ∃! x ∃ y ∈ A x = B ↔ ∃! x ∀ y ∈ A x = B
29 28 exlimdv ⊢ A ≠ ∅ → ∃ z ∀ y ∈ A z = B → ∃! x ∃ y ∈ A x = B ↔ ∃! x ∀ y ∈ A x = B
30 euex ⊢ ∃! x ∀ y ∈ A x = B → ∃ x ∀ y ∈ A x = B
31 16 cbvexvw ⊢ ∃ x ∀ y ∈ A x = B ↔ ∃ z ∀ y ∈ A z = B
32 30 31 sylib ⊢ ∃! x ∀ y ∈ A x = B → ∃ z ∀ y ∈ A z = B
33 29 32 impel ⊢ A ≠ ∅ ∧ ∃! x ∀ y ∈ A x = B → ∃! x ∃ y ∈ A x = B ↔ ∃! x ∀ y ∈ A x = B
34 8 33 mpbird ⊢ A ≠ ∅ ∧ ∃! x ∀ y ∈ A x = B → ∃! x ∃ y ∈ A x = B
35 34 ex ⊢ A ≠ ∅ → ∃! x ∀ y ∈ A x = B → ∃! x ∃ y ∈ A x = B
36 7 35 pm2.61ine ⊢ ∃! x ∀ y ∈ A x = B → ∃! x ∃ y ∈ A x = B