Metamath Proof Explorer


Theorem rexdiv

Description: The extended real division operation when both arguments are real. (Contributed by Thierry Arnoux, 18-Dec-2016)

Ref Expression
Assertion rexdiv ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ B ≠ 0 → A ÷ 𝑒 B = A B

Proof

Step Hyp Ref Expression
1 redivcl ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ B ≠ 0 → A B ∈ ℝ
2 recn ⊢ A ∈ ℝ → A ∈ ℂ
3 recn ⊢ B ∈ ℝ → B ∈ ℂ
4 id ⊢ B ≠ 0 → B ≠ 0
5 2 3 4 3anim123i ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ B ≠ 0 → A ∈ ℂ ∧ B ∈ ℂ ∧ B ≠ 0
6 divcan2 ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ B ≠ 0 → B ⁢ A B = A
7 5 6 syl ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ B ≠ 0 → B ⁢ A B = A
8 oveq2 ⊢ x = A B → B ⁢ x = B ⁢ A B
9 8 eqeq1d ⊢ x = A B → B ⁢ x = A ↔ B ⁢ A B = A
10 9 rspcev ⊢ A B ∈ ℝ ∧ B ⁢ A B = A → ∃ x ∈ ℝ B ⁢ x = A
11 1 7 10 syl2anc ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ B ≠ 0 → ∃ x ∈ ℝ B ⁢ x = A
12 receu ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ B ≠ 0 → ∃! x ∈ ℂ B ⁢ x = A
13 5 12 syl ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ B ≠ 0 → ∃! x ∈ ℂ B ⁢ x = A
14 ax-resscn ⊢ ℝ ⊆ ℂ
15 id ⊢ B ⁢ x = A → B ⁢ x = A
16 15 rgenw ⊢ ∀ x ∈ ℝ B ⁢ x = A → B ⁢ x = A
17 riotass2 ⊢ ℝ ⊆ ℂ ∧ ∀ x ∈ ℝ B ⁢ x = A → B ⁢ x = A ∧ ∃ x ∈ ℝ B ⁢ x = A ∧ ∃! x ∈ ℂ B ⁢ x = A → ι x ∈ ℝ | B ⁢ x = A = ι x ∈ ℂ | B ⁢ x = A
18 14 16 17 mpanl12 ⊢ ∃ x ∈ ℝ B ⁢ x = A ∧ ∃! x ∈ ℂ B ⁢ x = A → ι x ∈ ℝ | B ⁢ x = A = ι x ∈ ℂ | B ⁢ x = A
19 11 13 18 syl2anc ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ B ≠ 0 → ι x ∈ ℝ | B ⁢ x = A = ι x ∈ ℂ | B ⁢ x = A
20 rexr ⊢ A ∈ ℝ → A ∈ ℝ *
21 xdivval ⊢ A ∈ ℝ * ∧ B ∈ ℝ ∧ B ≠ 0 → A ÷ 𝑒 B = ι x ∈ ℝ * | B ⋅ 𝑒 x = A
22 20 21 syl3an1 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ B ≠ 0 → A ÷ 𝑒 B = ι x ∈ ℝ * | B ⋅ 𝑒 x = A
23 ressxr ⊢ ℝ ⊆ ℝ *
24 23 a1i ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ B ≠ 0 → ℝ ⊆ ℝ *
25 rexmul ⊢ B ∈ ℝ ∧ x ∈ ℝ → B ⋅ 𝑒 x = B ⁢ x
26 25 eqeq1d ⊢ B ∈ ℝ ∧ x ∈ ℝ → B ⋅ 𝑒 x = A ↔ B ⁢ x = A
27 26 biimprd ⊢ B ∈ ℝ ∧ x ∈ ℝ → B ⁢ x = A → B ⋅ 𝑒 x = A
28 27 ralrimiva ⊢ B ∈ ℝ → ∀ x ∈ ℝ B ⁢ x = A → B ⋅ 𝑒 x = A
29 28 3ad2ant2 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ B ≠ 0 → ∀ x ∈ ℝ B ⁢ x = A → B ⋅ 𝑒 x = A
30 xreceu ⊢ A ∈ ℝ * ∧ B ∈ ℝ ∧ B ≠ 0 → ∃! x ∈ ℝ * B ⋅ 𝑒 x = A
31 20 30 syl3an1 ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ B ≠ 0 → ∃! x ∈ ℝ * B ⋅ 𝑒 x = A
32 riotass2 ⊢ ℝ ⊆ ℝ * ∧ ∀ x ∈ ℝ B ⁢ x = A → B ⋅ 𝑒 x = A ∧ ∃ x ∈ ℝ B ⁢ x = A ∧ ∃! x ∈ ℝ * B ⋅ 𝑒 x = A → ι x ∈ ℝ | B ⁢ x = A = ι x ∈ ℝ * | B ⋅ 𝑒 x = A
33 24 29 11 31 32 syl22anc ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ B ≠ 0 → ι x ∈ ℝ | B ⁢ x = A = ι x ∈ ℝ * | B ⋅ 𝑒 x = A
34 22 33 eqtr4d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ B ≠ 0 → A ÷ 𝑒 B = ι x ∈ ℝ | B ⁢ x = A
35 divval ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ B ≠ 0 → A B = ι x ∈ ℂ | B ⁢ x = A
36 5 35 syl ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ B ≠ 0 → A B = ι x ∈ ℂ | B ⁢ x = A
37 19 34 36 3eqtr4d ⊢ A ∈ ℝ ∧ B ∈ ℝ ∧ B ≠ 0 → A ÷ 𝑒 B = A B