Metamath Proof Explorer


Theorem reximdd

Description: Deduction from Theorem 19.22 of Margaris p. 90. (Contributed by Glauco Siliprandi, 5-Feb-2022)

Ref Expression
Hypotheses reximdd.1 ⊢ Ⅎ x φ
reximdd.2 ⊢ φ ∧ x ∈ A ∧ ψ → χ
reximdd.3 ⊢ φ → ∃ x ∈ A ψ
Assertion reximdd ⊢ φ → ∃ x ∈ A χ

Proof

Step Hyp Ref Expression
1 reximdd.1 ⊢ Ⅎ x φ
2 reximdd.2 ⊢ φ ∧ x ∈ A ∧ ψ → χ
3 reximdd.3 ⊢ φ → ∃ x ∈ A ψ
4 2 3exp ⊢ φ → x ∈ A → ψ → χ
5 1 4 reximdai ⊢ φ → ∃ x ∈ A ψ → ∃ x ∈ A χ
6 3 5 mpd ⊢ φ → ∃ x ∈ A χ