Metamath Proof Explorer


Theorem ringinvval

Description: The ring inverse expressed in terms of multiplication. (Contributed by Thierry Arnoux, 23-Oct-2017)

Ref Expression
Hypotheses ringinvval.b ⊢ B = Base R
ringinvval.p ⊢ ∗ ˙ = ⋅ R
ringinvval.o ⊢ 1 ˙ = 1 R
ringinvval.n ⊢ N = inv r ⁡ R
ringinvval.u ⊢ U = Unit ⁡ R
Assertion ringinvval ⊢ R ∈ Ring ∧ X ∈ U → N ⁡ X = ι y ∈ U | y ∗ ˙ X = 1 ˙

Proof

Step Hyp Ref Expression
1 ringinvval.b ⊢ B = Base R
2 ringinvval.p ⊢ ∗ ˙ = ⋅ R
3 ringinvval.o ⊢ 1 ˙ = 1 R
4 ringinvval.n ⊢ N = inv r ⁡ R
5 ringinvval.u ⊢ U = Unit ⁡ R
6 eqid ⊢ mulGrp R ↾ 𝑠 U = mulGrp R ↾ 𝑠 U
7 5 6 unitgrpbas ⊢ U = Base mulGrp R ↾ 𝑠 U
8 5 fvexi ⊢ U ∈ V
9 eqid ⊢ mulGrp R = mulGrp R
10 9 2 mgpplusg ⊢ ∗ ˙ = + mulGrp R
11 6 10 ressplusg ⊢ U ∈ V → ∗ ˙ = + mulGrp R ↾ 𝑠 U
12 8 11 ax-mp ⊢ ∗ ˙ = + mulGrp R ↾ 𝑠 U
13 eqid ⊢ 0 mulGrp R ↾ 𝑠 U = 0 mulGrp R ↾ 𝑠 U
14 5 6 4 invrfval ⊢ N = inv g ⁡ mulGrp R ↾ 𝑠 U
15 7 12 13 14 grpinvval ⊢ X ∈ U → N ⁡ X = ι y ∈ U | y ∗ ˙ X = 0 mulGrp R ↾ 𝑠 U
16 15 adantl ⊢ R ∈ Ring ∧ X ∈ U → N ⁡ X = ι y ∈ U | y ∗ ˙ X = 0 mulGrp R ↾ 𝑠 U
17 5 6 3 unitgrpid ⊢ R ∈ Ring → 1 ˙ = 0 mulGrp R ↾ 𝑠 U
18 17 adantr ⊢ R ∈ Ring ∧ y ∈ U → 1 ˙ = 0 mulGrp R ↾ 𝑠 U
19 18 eqeq2d ⊢ R ∈ Ring ∧ y ∈ U → y ∗ ˙ X = 1 ˙ ↔ y ∗ ˙ X = 0 mulGrp R ↾ 𝑠 U
20 19 riotabidva ⊢ R ∈ Ring → ι y ∈ U | y ∗ ˙ X = 1 ˙ = ι y ∈ U | y ∗ ˙ X = 0 mulGrp R ↾ 𝑠 U
21 20 adantr ⊢ R ∈ Ring ∧ X ∈ U → ι y ∈ U | y ∗ ˙ X = 1 ˙ = ι y ∈ U | y ∗ ˙ X = 0 mulGrp R ↾ 𝑠 U
22 16 21 eqtr4d ⊢ R ∈ Ring ∧ X ∈ U → N ⁡ X = ι y ∈ U | y ∗ ˙ X = 1 ˙