Metamath Proof Explorer


Theorem risefallfac

Description: A relationship between rising and falling factorials. (Contributed by Scott Fenton, 15-Jan-2018)

Ref Expression
Assertion risefallfac ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 → X N ‾ = − 1 N ⁢ − X N _

Proof

Step Hyp Ref Expression
1 negcl ⊢ X ∈ ℂ → − X ∈ ℂ
2 1 adantr ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 → − X ∈ ℂ
3 elfznn ⊢ k ∈ 1 … N → k ∈ ℕ
4 nnm1nn0 ⊢ k ∈ ℕ → k − 1 ∈ ℕ 0
5 3 4 syl ⊢ k ∈ 1 … N → k − 1 ∈ ℕ 0
6 5 nn0cnd ⊢ k ∈ 1 … N → k − 1 ∈ ℂ
7 subcl ⊢ − X ∈ ℂ ∧ k − 1 ∈ ℂ → - X - k − 1 ∈ ℂ
8 2 6 7 syl2an ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 ∧ k ∈ 1 … N → - X - k − 1 ∈ ℂ
9 8 mulm1d ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 ∧ k ∈ 1 … N → -1 ⁢ - X - k − 1 = − - X - k − 1
10 simpll ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 ∧ k ∈ 1 … N → X ∈ ℂ
11 6 adantl ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 ∧ k ∈ 1 … N → k − 1 ∈ ℂ
12 10 11 negdi2d ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 ∧ k ∈ 1 … N → − X + k - 1 = - X - k − 1
13 12 negeqd ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 ∧ k ∈ 1 … N → − − X + k - 1 = − - X - k − 1
14 simpl ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 → X ∈ ℂ
15 addcl ⊢ X ∈ ℂ ∧ k − 1 ∈ ℂ → X + k - 1 ∈ ℂ
16 14 6 15 syl2an ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 ∧ k ∈ 1 … N → X + k - 1 ∈ ℂ
17 16 negnegd ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 ∧ k ∈ 1 … N → − − X + k - 1 = X + k - 1
18 9 13 17 3eqtr2rd ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 ∧ k ∈ 1 … N → X + k - 1 = -1 ⁢ - X - k − 1
19 18 prodeq2dv ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 → ∏ k = 1 N X + k - 1 = ∏ k = 1 N -1 ⁢ - X - k − 1
20 risefacval2 ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 → X N ‾ = ∏ k = 1 N X + k - 1
21 fzfi ⊢ 1 … N ∈ Fin
22 neg1cn ⊢ − 1 ∈ ℂ
23 fprodconst ⊢ 1 … N ∈ Fin ∧ − 1 ∈ ℂ → ∏ k = 1 N -1 = − 1 1 … N
24 21 22 23 mp2an ⊢ ∏ k = 1 N -1 = − 1 1 … N
25 hashfz1 ⊢ N ∈ ℕ 0 → 1 … N = N
26 25 oveq2d ⊢ N ∈ ℕ 0 → − 1 1 … N = − 1 N
27 24 26 eqtr2id ⊢ N ∈ ℕ 0 → − 1 N = ∏ k = 1 N -1
28 27 adantl ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 → − 1 N = ∏ k = 1 N -1
29 fallfacval2 ⊢ − X ∈ ℂ ∧ N ∈ ℕ 0 → − X N _ = ∏ k = 1 N - X - k − 1
30 1 29 sylan ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 → − X N _ = ∏ k = 1 N - X - k − 1
31 28 30 oveq12d ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 → − 1 N ⁢ − X N _ = ∏ k = 1 N -1 ⁢ ∏ k = 1 N - X - k − 1
32 fzfid ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 → 1 … N ∈ Fin
33 22 a1i ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 ∧ k ∈ 1 … N → − 1 ∈ ℂ
34 32 33 8 fprodmul ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 → ∏ k = 1 N -1 ⁢ - X - k − 1 = ∏ k = 1 N -1 ⁢ ∏ k = 1 N - X - k − 1
35 31 34 eqtr4d ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 → − 1 N ⁢ − X N _ = ∏ k = 1 N -1 ⁢ - X - k − 1
36 19 20 35 3eqtr4d ⊢ X ∈ ℂ ∧ N ∈ ℕ 0 → X N ‾ = − 1 N ⁢ − X N _