Metamath Proof Explorer


Theorem rmxadd

Description: Addition formula for X sequence. Equation 2.7 of JonesMatijasevic p. 695. (Contributed by Stefan O'Rear, 22-Sep-2014)

Ref Expression
Assertion rmxadd ⊢ A ∈ ℤ ≥ 2 ∧ M ∈ ℤ ∧ N ∈ ℤ → A X rm M + N = A X rm M ⁢ A X rm N + A 2 − 1 ⁢ A Y rm M ⁢ A Y rm N

Proof

Step Hyp Ref Expression
1 rmxyadd ⊢ A ∈ ℤ ≥ 2 ∧ M ∈ ℤ ∧ N ∈ ℤ → A X rm M + N = A X rm M ⁢ A X rm N + A 2 − 1 ⁢ A Y rm M ⁢ A Y rm N ∧ A Y rm M + N = A Y rm M ⁢ A X rm N + A X rm M ⁢ A Y rm N
2 1 simpld ⊢ A ∈ ℤ ≥ 2 ∧ M ∈ ℤ ∧ N ∈ ℤ → A X rm M + N = A X rm M ⁢ A X rm N + A 2 − 1 ⁢ A Y rm M ⁢ A Y rm N