Metamath Proof Explorer


Theorem rncoss

Description: Range of a composition. (Contributed by NM, 19-Mar-1998)

Ref Expression
Assertion rncoss ⊢ ran ⁡ A ∘ B ⊆ ran ⁡ A

Proof

Step Hyp Ref Expression
1 dmcoss ⊢ dom ⁡ B -1 ∘ A -1 ⊆ dom ⁡ A -1
2 df-rn ⊢ ran ⁡ A ∘ B = dom ⁡ A ∘ B -1
3 cnvco ⊢ A ∘ B -1 = B -1 ∘ A -1
4 3 dmeqi ⊢ dom ⁡ A ∘ B -1 = dom ⁡ B -1 ∘ A -1
5 2 4 eqtri ⊢ ran ⁡ A ∘ B = dom ⁡ B -1 ∘ A -1
6 df-rn ⊢ ran ⁡ A = dom ⁡ A -1
7 1 5 6 3sstr4i ⊢ ran ⁡ A ∘ B ⊆ ran ⁡ A