Metamath Proof Explorer


Theorem rspcdf

Description: Restricted specialization, using implicit substitution. (Contributed by Emmett Weisz, 16-Jan-2020)

Ref Expression
Hypotheses rspcdf.1 ⊢ Ⅎ x φ
rspcdf.2 ⊢ Ⅎ x χ
rspcdf.3 ⊢ φ → A ∈ B
rspcdf.4 ⊢ φ ∧ x = A → ψ ↔ χ
Assertion rspcdf ⊢ φ → ∀ x ∈ B ψ → χ

Proof

Step Hyp Ref Expression
1 rspcdf.1 ⊢ Ⅎ x φ
2 rspcdf.2 ⊢ Ⅎ x χ
3 rspcdf.3 ⊢ φ → A ∈ B
4 rspcdf.4 ⊢ φ ∧ x = A → ψ ↔ χ
5 4 ex ⊢ φ → x = A → ψ ↔ χ
6 1 5 alrimi ⊢ φ → ∀ x x = A → ψ ↔ χ
7 2 rspct ⊢ ∀ x x = A → ψ ↔ χ → A ∈ B → ∀ x ∈ B ψ → χ
8 6 3 7 sylc ⊢ φ → ∀ x ∈ B ψ → χ