Metamath Proof Explorer


Theorem sbcied2

Description: Conversion of implicit substitution to explicit class substitution, deduction form. (Contributed by NM, 13-Dec-2014)

Ref Expression
Hypotheses sbcied2.1 ⊢ φ → A ∈ V
sbcied2.2 ⊢ φ → A = B
sbcied2.3 ⊢ φ ∧ x = B → ψ ↔ χ
Assertion sbcied2 ⊢ φ → [˙A / x]˙ ψ ↔ χ

Proof

Step Hyp Ref Expression
1 sbcied2.1 ⊢ φ → A ∈ V
2 sbcied2.2 ⊢ φ → A = B
3 sbcied2.3 ⊢ φ ∧ x = B → ψ ↔ χ
4 id ⊢ x = A → x = A
5 4 2 sylan9eqr ⊢ φ ∧ x = A → x = B
6 5 3 syldan ⊢ φ ∧ x = A → ψ ↔ χ
7 1 6 sbcied ⊢ φ → [˙A / x]˙ ψ ↔ χ