Metamath Proof Explorer
Description: An equality theorem for substitution. (Contributed by NM, 6-Oct-2004)
(Proof shortened by Andrew Salmon, 21-Jun-2011)
|
|
Ref |
Expression |
|
Assertion |
sbequ12r |
|
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
sbequ12 |
|
2 |
1
|
bicomd |
|
3 |
2
|
equcoms |
|