Metamath Proof Explorer


Theorem sdrgss

Description: A division subring is a subset of the base set. (Contributed by Thierry Arnoux, 21-Aug-2023)

Ref Expression
Hypothesis sdrgid.1 ⊢ B = Base R
Assertion sdrgss ⊢ S ∈ SubDRing ⁡ R → S ⊆ B

Proof

Step Hyp Ref Expression
1 sdrgid.1 ⊢ B = Base R
2 issdrg ⊢ S ∈ SubDRing ⁡ R ↔ R ∈ DivRing ∧ S ∈ SubRing ⁡ R ∧ R ↾ 𝑠 S ∈ DivRing
3 1 subrgss ⊢ S ∈ SubRing ⁡ R → S ⊆ B
4 3 3ad2ant2 ⊢ R ∈ DivRing ∧ S ∈ SubRing ⁡ R ∧ R ↾ 𝑠 S ∈ DivRing → S ⊆ B
5 2 4 sylbi ⊢ S ∈ SubDRing ⁡ R → S ⊆ B