Metamath Proof Explorer


Theorem sectpropdlem

Description: Lemma for sectpropd . (Contributed by Zhi Wang, 27-Oct-2025)

Ref Expression
Hypotheses sectpropd.1 ⊢ φ → Hom 𝑓 ⁡ C = Hom 𝑓 ⁡ D
sectpropd.2 ⊢ φ → comp 𝑓 ⁡ C = comp 𝑓 ⁡ D
Assertion sectpropdlem ⊢ φ ∧ P ∈ Sect ⁡ C → P ∈ Sect ⁡ D

Proof

Step Hyp Ref Expression
1 sectpropd.1 ⊢ φ → Hom 𝑓 ⁡ C = Hom 𝑓 ⁡ D
2 sectpropd.2 ⊢ φ → comp 𝑓 ⁡ C = comp 𝑓 ⁡ D
3 simpr ⊢ φ ∧ P ∈ Sect ⁡ C → P ∈ Sect ⁡ C
4 eqid ⊢ Base C = Base C
5 eqid ⊢ Hom ⁡ C = Hom ⁡ C
6 eqid ⊢ comp ⁡ C = comp ⁡ C
7 eqid ⊢ Id ⁡ C = Id ⁡ C
8 eqid ⊢ Sect ⁡ C = Sect ⁡ C
9 df-sect ⊢ Sect = c ∈ Cat ⟼ x ∈ Base c , y ∈ Base c ⟼ f g | [˙ Hom ⁡ c / h]˙ f ∈ x h y ∧ g ∈ y h x ∧ g x y comp ⁡ c x f = Id ⁡ c ⁡ x
10 9 mptrcl ⊢ P ∈ Sect ⁡ C → C ∈ Cat
11 10 adantl ⊢ φ ∧ P ∈ Sect ⁡ C → C ∈ Cat
12 4 5 6 7 8 11 sectffval ⊢ φ ∧ P ∈ Sect ⁡ C → Sect ⁡ C = x ∈ Base C , y ∈ Base C ⟼ f g | f ∈ x Hom ⁡ C y ∧ g ∈ y Hom ⁡ C x ∧ g x y comp ⁡ C x f = Id ⁡ C ⁡ x
13 df-mpo ⊢ x ∈ Base C , y ∈ Base C ⟼ f g | f ∈ x Hom ⁡ C y ∧ g ∈ y Hom ⁡ C x ∧ g x y comp ⁡ C x f = Id ⁡ C ⁡ x = x y z | x ∈ Base C ∧ y ∈ Base C ∧ z = f g | f ∈ x Hom ⁡ C y ∧ g ∈ y Hom ⁡ C x ∧ g x y comp ⁡ C x f = Id ⁡ C ⁡ x
14 12 13 eqtrdi ⊢ φ ∧ P ∈ Sect ⁡ C → Sect ⁡ C = x y z | x ∈ Base C ∧ y ∈ Base C ∧ z = f g | f ∈ x Hom ⁡ C y ∧ g ∈ y Hom ⁡ C x ∧ g x y comp ⁡ C x f = Id ⁡ C ⁡ x
15 3 14 eleqtrd ⊢ φ ∧ P ∈ Sect ⁡ C → P ∈ x y z | x ∈ Base C ∧ y ∈ Base C ∧ z = f g | f ∈ x Hom ⁡ C y ∧ g ∈ y Hom ⁡ C x ∧ g x y comp ⁡ C x f = Id ⁡ C ⁡ x
16 eloprab1st2nd ⊢ P ∈ x y z | x ∈ Base C ∧ y ∈ Base C ∧ z = f g | f ∈ x Hom ⁡ C y ∧ g ∈ y Hom ⁡ C x ∧ g x y comp ⁡ C x f = Id ⁡ C ⁡ x → P = 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P 2 nd ⁡ P
17 15 16 syl ⊢ φ ∧ P ∈ Sect ⁡ C → P = 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P 2 nd ⁡ P
18 eqid ⊢ comp ⁡ D = comp ⁡ D
19 1 adantr ⊢ φ ∧ P ∈ Sect ⁡ C → Hom 𝑓 ⁡ C = Hom 𝑓 ⁡ D
20 19 adantr ⊢ φ ∧ P ∈ Sect ⁡ C ∧ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P → Hom 𝑓 ⁡ C = Hom 𝑓 ⁡ D
21 2 adantr ⊢ φ ∧ P ∈ Sect ⁡ C → comp 𝑓 ⁡ C = comp 𝑓 ⁡ D
22 21 adantr ⊢ φ ∧ P ∈ Sect ⁡ C ∧ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P → comp 𝑓 ⁡ C = comp 𝑓 ⁡ D
23 eleq1 ⊢ x = 1 st ⁡ 1 st ⁡ P → x ∈ Base C ↔ 1 st ⁡ 1 st ⁡ P ∈ Base C
24 23 anbi1d ⊢ x = 1 st ⁡ 1 st ⁡ P → x ∈ Base C ∧ y ∈ Base C ↔ 1 st ⁡ 1 st ⁡ P ∈ Base C ∧ y ∈ Base C
25 oveq1 ⊢ x = 1 st ⁡ 1 st ⁡ P → x Hom ⁡ C y = 1 st ⁡ 1 st ⁡ P Hom ⁡ C y
26 25 eleq2d ⊢ x = 1 st ⁡ 1 st ⁡ P → f ∈ x Hom ⁡ C y ↔ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C y
27 oveq2 ⊢ x = 1 st ⁡ 1 st ⁡ P → y Hom ⁡ C x = y Hom ⁡ C 1 st ⁡ 1 st ⁡ P
28 27 eleq2d ⊢ x = 1 st ⁡ 1 st ⁡ P → g ∈ y Hom ⁡ C x ↔ g ∈ y Hom ⁡ C 1 st ⁡ 1 st ⁡ P
29 26 28 anbi12d ⊢ x = 1 st ⁡ 1 st ⁡ P → f ∈ x Hom ⁡ C y ∧ g ∈ y Hom ⁡ C x ↔ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C y ∧ g ∈ y Hom ⁡ C 1 st ⁡ 1 st ⁡ P
30 opeq1 ⊢ x = 1 st ⁡ 1 st ⁡ P → x y = 1 st ⁡ 1 st ⁡ P y
31 id ⊢ x = 1 st ⁡ 1 st ⁡ P → x = 1 st ⁡ 1 st ⁡ P
32 30 31 oveq12d ⊢ x = 1 st ⁡ 1 st ⁡ P → x y comp ⁡ C x = 1 st ⁡ 1 st ⁡ P y comp ⁡ C 1 st ⁡ 1 st ⁡ P
33 32 oveqd ⊢ x = 1 st ⁡ 1 st ⁡ P → g x y comp ⁡ C x f = g 1 st ⁡ 1 st ⁡ P y comp ⁡ C 1 st ⁡ 1 st ⁡ P f
34 fveq2 ⊢ x = 1 st ⁡ 1 st ⁡ P → Id ⁡ C ⁡ x = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P
35 33 34 eqeq12d ⊢ x = 1 st ⁡ 1 st ⁡ P → g x y comp ⁡ C x f = Id ⁡ C ⁡ x ↔ g 1 st ⁡ 1 st ⁡ P y comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P
36 29 35 anbi12d ⊢ x = 1 st ⁡ 1 st ⁡ P → f ∈ x Hom ⁡ C y ∧ g ∈ y Hom ⁡ C x ∧ g x y comp ⁡ C x f = Id ⁡ C ⁡ x ↔ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C y ∧ g ∈ y Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P y comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P
37 36 opabbidv ⊢ x = 1 st ⁡ 1 st ⁡ P → f g | f ∈ x Hom ⁡ C y ∧ g ∈ y Hom ⁡ C x ∧ g x y comp ⁡ C x f = Id ⁡ C ⁡ x = f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C y ∧ g ∈ y Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P y comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P
38 37 eqeq2d ⊢ x = 1 st ⁡ 1 st ⁡ P → z = f g | f ∈ x Hom ⁡ C y ∧ g ∈ y Hom ⁡ C x ∧ g x y comp ⁡ C x f = Id ⁡ C ⁡ x ↔ z = f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C y ∧ g ∈ y Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P y comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P
39 24 38 anbi12d ⊢ x = 1 st ⁡ 1 st ⁡ P → x ∈ Base C ∧ y ∈ Base C ∧ z = f g | f ∈ x Hom ⁡ C y ∧ g ∈ y Hom ⁡ C x ∧ g x y comp ⁡ C x f = Id ⁡ C ⁡ x ↔ 1 st ⁡ 1 st ⁡ P ∈ Base C ∧ y ∈ Base C ∧ z = f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C y ∧ g ∈ y Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P y comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P
40 eleq1 ⊢ y = 2 nd ⁡ 1 st ⁡ P → y ∈ Base C ↔ 2 nd ⁡ 1 st ⁡ P ∈ Base C
41 40 anbi2d ⊢ y = 2 nd ⁡ 1 st ⁡ P → 1 st ⁡ 1 st ⁡ P ∈ Base C ∧ y ∈ Base C ↔ 1 st ⁡ 1 st ⁡ P ∈ Base C ∧ 2 nd ⁡ 1 st ⁡ P ∈ Base C
42 oveq2 ⊢ y = 2 nd ⁡ 1 st ⁡ P → 1 st ⁡ 1 st ⁡ P Hom ⁡ C y = 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P
43 42 eleq2d ⊢ y = 2 nd ⁡ 1 st ⁡ P → f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C y ↔ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P
44 oveq1 ⊢ y = 2 nd ⁡ 1 st ⁡ P → y Hom ⁡ C 1 st ⁡ 1 st ⁡ P = 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P
45 44 eleq2d ⊢ y = 2 nd ⁡ 1 st ⁡ P → g ∈ y Hom ⁡ C 1 st ⁡ 1 st ⁡ P ↔ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P
46 43 45 anbi12d ⊢ y = 2 nd ⁡ 1 st ⁡ P → f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C y ∧ g ∈ y Hom ⁡ C 1 st ⁡ 1 st ⁡ P ↔ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P
47 opeq2 ⊢ y = 2 nd ⁡ 1 st ⁡ P → 1 st ⁡ 1 st ⁡ P y = 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P
48 47 oveq1d ⊢ y = 2 nd ⁡ 1 st ⁡ P → 1 st ⁡ 1 st ⁡ P y comp ⁡ C 1 st ⁡ 1 st ⁡ P = 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P
49 48 oveqd ⊢ y = 2 nd ⁡ 1 st ⁡ P → g 1 st ⁡ 1 st ⁡ P y comp ⁡ C 1 st ⁡ 1 st ⁡ P f = g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P f
50 49 eqeq1d ⊢ y = 2 nd ⁡ 1 st ⁡ P → g 1 st ⁡ 1 st ⁡ P y comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P ↔ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P
51 46 50 anbi12d ⊢ y = 2 nd ⁡ 1 st ⁡ P → f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C y ∧ g ∈ y Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P y comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P ↔ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P
52 51 opabbidv ⊢ y = 2 nd ⁡ 1 st ⁡ P → f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C y ∧ g ∈ y Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P y comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P = f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P
53 52 eqeq2d ⊢ y = 2 nd ⁡ 1 st ⁡ P → z = f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C y ∧ g ∈ y Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P y comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P ↔ z = f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P
54 41 53 anbi12d ⊢ y = 2 nd ⁡ 1 st ⁡ P → 1 st ⁡ 1 st ⁡ P ∈ Base C ∧ y ∈ Base C ∧ z = f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C y ∧ g ∈ y Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P y comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P ↔ 1 st ⁡ 1 st ⁡ P ∈ Base C ∧ 2 nd ⁡ 1 st ⁡ P ∈ Base C ∧ z = f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P
55 eqeq1 ⊢ z = 2 nd ⁡ P → z = f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P ↔ 2 nd ⁡ P = f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P
56 55 anbi2d ⊢ z = 2 nd ⁡ P → 1 st ⁡ 1 st ⁡ P ∈ Base C ∧ 2 nd ⁡ 1 st ⁡ P ∈ Base C ∧ z = f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P ↔ 1 st ⁡ 1 st ⁡ P ∈ Base C ∧ 2 nd ⁡ 1 st ⁡ P ∈ Base C ∧ 2 nd ⁡ P = f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P
57 39 54 56 eloprabi ⊢ P ∈ x y z | x ∈ Base C ∧ y ∈ Base C ∧ z = f g | f ∈ x Hom ⁡ C y ∧ g ∈ y Hom ⁡ C x ∧ g x y comp ⁡ C x f = Id ⁡ C ⁡ x → 1 st ⁡ 1 st ⁡ P ∈ Base C ∧ 2 nd ⁡ 1 st ⁡ P ∈ Base C ∧ 2 nd ⁡ P = f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P
58 15 57 syl ⊢ φ ∧ P ∈ Sect ⁡ C → 1 st ⁡ 1 st ⁡ P ∈ Base C ∧ 2 nd ⁡ 1 st ⁡ P ∈ Base C ∧ 2 nd ⁡ P = f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P
59 58 simplld ⊢ φ ∧ P ∈ Sect ⁡ C → 1 st ⁡ 1 st ⁡ P ∈ Base C
60 59 adantr ⊢ φ ∧ P ∈ Sect ⁡ C ∧ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P → 1 st ⁡ 1 st ⁡ P ∈ Base C
61 58 simplrd ⊢ φ ∧ P ∈ Sect ⁡ C → 2 nd ⁡ 1 st ⁡ P ∈ Base C
62 61 adantr ⊢ φ ∧ P ∈ Sect ⁡ C ∧ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P → 2 nd ⁡ 1 st ⁡ P ∈ Base C
63 simprl ⊢ φ ∧ P ∈ Sect ⁡ C ∧ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P → f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P
64 simprr ⊢ φ ∧ P ∈ Sect ⁡ C ∧ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P → g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P
65 4 5 6 18 20 22 60 62 60 63 64 comfeqval ⊢ φ ∧ P ∈ Sect ⁡ C ∧ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P → g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P f = g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ D 1 st ⁡ 1 st ⁡ P f
66 19 homfeqbas ⊢ φ ∧ P ∈ Sect ⁡ C → Base C = Base D
67 59 66 eleqtrd ⊢ φ ∧ P ∈ Sect ⁡ C → 1 st ⁡ 1 st ⁡ P ∈ Base D
68 67 elfvexd ⊢ φ ∧ P ∈ Sect ⁡ C → D ∈ V
69 19 21 11 68 cidpropd ⊢ φ ∧ P ∈ Sect ⁡ C → Id ⁡ C = Id ⁡ D
70 69 fveq1d ⊢ φ ∧ P ∈ Sect ⁡ C → Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P = Id ⁡ D ⁡ 1 st ⁡ 1 st ⁡ P
71 70 adantr ⊢ φ ∧ P ∈ Sect ⁡ C ∧ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P → Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P = Id ⁡ D ⁡ 1 st ⁡ 1 st ⁡ P
72 65 71 eqeq12d ⊢ φ ∧ P ∈ Sect ⁡ C ∧ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P → g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P ↔ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ D 1 st ⁡ 1 st ⁡ P f = Id ⁡ D ⁡ 1 st ⁡ 1 st ⁡ P
73 72 pm5.32da ⊢ φ ∧ P ∈ Sect ⁡ C → f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P ↔ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ D 1 st ⁡ 1 st ⁡ P f = Id ⁡ D ⁡ 1 st ⁡ 1 st ⁡ P
74 eqid ⊢ Hom ⁡ D = Hom ⁡ D
75 4 5 74 19 59 61 homfeqval ⊢ φ ∧ P ∈ Sect ⁡ C → 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P = 1 st ⁡ 1 st ⁡ P Hom ⁡ D 2 nd ⁡ 1 st ⁡ P
76 75 eleq2d ⊢ φ ∧ P ∈ Sect ⁡ C → f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ↔ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ D 2 nd ⁡ 1 st ⁡ P
77 4 5 74 19 61 59 homfeqval ⊢ φ ∧ P ∈ Sect ⁡ C → 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P = 2 nd ⁡ 1 st ⁡ P Hom ⁡ D 1 st ⁡ 1 st ⁡ P
78 77 eleq2d ⊢ φ ∧ P ∈ Sect ⁡ C → g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P ↔ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ D 1 st ⁡ 1 st ⁡ P
79 76 78 anbi12d ⊢ φ ∧ P ∈ Sect ⁡ C → f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P ↔ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ D 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ D 1 st ⁡ 1 st ⁡ P
80 79 anbi1d ⊢ φ ∧ P ∈ Sect ⁡ C → f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ D 1 st ⁡ 1 st ⁡ P f = Id ⁡ D ⁡ 1 st ⁡ 1 st ⁡ P ↔ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ D 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ D 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ D 1 st ⁡ 1 st ⁡ P f = Id ⁡ D ⁡ 1 st ⁡ 1 st ⁡ P
81 73 80 bitrd ⊢ φ ∧ P ∈ Sect ⁡ C → f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P ↔ f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ D 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ D 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ D 1 st ⁡ 1 st ⁡ P f = Id ⁡ D ⁡ 1 st ⁡ 1 st ⁡ P
82 81 opabbidv ⊢ φ ∧ P ∈ Sect ⁡ C → f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P = f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ D 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ D 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ D 1 st ⁡ 1 st ⁡ P f = Id ⁡ D ⁡ 1 st ⁡ 1 st ⁡ P
83 58 simprd ⊢ φ ∧ P ∈ Sect ⁡ C → 2 nd ⁡ P = f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ C 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ C 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ C 1 st ⁡ 1 st ⁡ P f = Id ⁡ C ⁡ 1 st ⁡ 1 st ⁡ P
84 eqid ⊢ Base D = Base D
85 eqid ⊢ Id ⁡ D = Id ⁡ D
86 eqid ⊢ Sect ⁡ D = Sect ⁡ D
87 19 21 11 68 catpropd ⊢ φ ∧ P ∈ Sect ⁡ C → C ∈ Cat ↔ D ∈ Cat
88 11 87 mpbid ⊢ φ ∧ P ∈ Sect ⁡ C → D ∈ Cat
89 61 66 eleqtrd ⊢ φ ∧ P ∈ Sect ⁡ C → 2 nd ⁡ 1 st ⁡ P ∈ Base D
90 84 74 18 85 86 88 67 89 sectfval ⊢ φ ∧ P ∈ Sect ⁡ C → 1 st ⁡ 1 st ⁡ P Sect ⁡ D 2 nd ⁡ 1 st ⁡ P = f g | f ∈ 1 st ⁡ 1 st ⁡ P Hom ⁡ D 2 nd ⁡ 1 st ⁡ P ∧ g ∈ 2 nd ⁡ 1 st ⁡ P Hom ⁡ D 1 st ⁡ 1 st ⁡ P ∧ g 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P comp ⁡ D 1 st ⁡ 1 st ⁡ P f = Id ⁡ D ⁡ 1 st ⁡ 1 st ⁡ P
91 82 83 90 3eqtr4rd ⊢ φ ∧ P ∈ Sect ⁡ C → 1 st ⁡ 1 st ⁡ P Sect ⁡ D 2 nd ⁡ 1 st ⁡ P = 2 nd ⁡ P
92 sectfn ⊢ D ∈ Cat → Sect ⁡ D Fn Base D × Base D
93 88 92 syl ⊢ φ ∧ P ∈ Sect ⁡ C → Sect ⁡ D Fn Base D × Base D
94 fnbrovb ⊢ Sect ⁡ D Fn Base D × Base D ∧ 1 st ⁡ 1 st ⁡ P ∈ Base D ∧ 2 nd ⁡ 1 st ⁡ P ∈ Base D → 1 st ⁡ 1 st ⁡ P Sect ⁡ D 2 nd ⁡ 1 st ⁡ P = 2 nd ⁡ P ↔ 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P Sect ⁡ D 2 nd ⁡ P
95 93 67 89 94 syl12anc ⊢ φ ∧ P ∈ Sect ⁡ C → 1 st ⁡ 1 st ⁡ P Sect ⁡ D 2 nd ⁡ 1 st ⁡ P = 2 nd ⁡ P ↔ 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P Sect ⁡ D 2 nd ⁡ P
96 91 95 mpbid ⊢ φ ∧ P ∈ Sect ⁡ C → 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P Sect ⁡ D 2 nd ⁡ P
97 df-br ⊢ 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P Sect ⁡ D 2 nd ⁡ P ↔ 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P 2 nd ⁡ P ∈ Sect ⁡ D
98 96 97 sylib ⊢ φ ∧ P ∈ Sect ⁡ C → 1 st ⁡ 1 st ⁡ P 2 nd ⁡ 1 st ⁡ P 2 nd ⁡ P ∈ Sect ⁡ D
99 17 98 eqeltrd ⊢ φ ∧ P ∈ Sect ⁡ C → P ∈ Sect ⁡ D