Metamath Proof Explorer


Theorem sepgi

Description: Inference associated with sepg . The requirement that y not occur in ph is necessary, as notsep shows. (Contributed by NM, 21-Jun-1993) (Revised by BJ, 14-Jul-2026)

Ref Expression
Hypothesis sepgi.1 ⊢ A ∈ V
Assertion sepgi ⊢ ∃ y ∀ x x ∈ y ↔ x ∈ A ∧ φ

Proof

Step Hyp Ref Expression
1 sepgi.1 ⊢ A ∈ V
2 sepg ⊢ A ∈ V → ∃ y ∀ x x ∈ y ↔ x ∈ A ∧ φ
3 1 2 ax-mp ⊢ ∃ y ∀ x x ∈ y ↔ x ∈ A ∧ φ