Metamath Proof Explorer


Theorem seqz

Description: If the operation .+ has an absorbing element Z (a.k.a. zero element), then any sequence containing a Z evaluates to Z . (Contributed by Mario Carneiro, 27-May-2014)

Ref Expression
Hypotheses seqhomo.1 ⊢ φ ∧ x ∈ S ∧ y ∈ S → x + ˙ y ∈ S
seqhomo.2 ⊢ φ ∧ x ∈ M … N → F ⁡ x ∈ S
seqz.3 ⊢ φ ∧ x ∈ S → Z + ˙ x = Z
seqz.4 ⊢ φ ∧ x ∈ S → x + ˙ Z = Z
seqz.5 ⊢ φ → K ∈ M … N
seqz.6 ⊢ φ → N ∈ V
seqz.7 ⊢ φ → F ⁡ K = Z
Assertion seqz ⊢ φ → seq M + ˙ F ⁡ N = Z

Proof

Step Hyp Ref Expression
1 seqhomo.1 ⊢ φ ∧ x ∈ S ∧ y ∈ S → x + ˙ y ∈ S
2 seqhomo.2 ⊢ φ ∧ x ∈ M … N → F ⁡ x ∈ S
3 seqz.3 ⊢ φ ∧ x ∈ S → Z + ˙ x = Z
4 seqz.4 ⊢ φ ∧ x ∈ S → x + ˙ Z = Z
5 seqz.5 ⊢ φ → K ∈ M … N
6 seqz.6 ⊢ φ → N ∈ V
7 seqz.7 ⊢ φ → F ⁡ K = Z
8 elfzuz ⊢ K ∈ M … N → K ∈ ℤ ≥ M
9 5 8 syl ⊢ φ → K ∈ ℤ ≥ M
10 5 elfzelzd ⊢ φ → K ∈ ℤ
11 seq1 ⊢ K ∈ ℤ → seq K + ˙ F ⁡ K = F ⁡ K
12 10 11 syl ⊢ φ → seq K + ˙ F ⁡ K = F ⁡ K
13 12 7 eqtrd ⊢ φ → seq K + ˙ F ⁡ K = Z
14 seqeq1 ⊢ K = M → seq K + ˙ F = seq M + ˙ F
15 14 fveq1d ⊢ K = M → seq K + ˙ F ⁡ K = seq M + ˙ F ⁡ K
16 15 eqeq1d ⊢ K = M → seq K + ˙ F ⁡ K = Z ↔ seq M + ˙ F ⁡ K = Z
17 13 16 syl5ibcom ⊢ φ → K = M → seq M + ˙ F ⁡ K = Z
18 eluzel2 ⊢ K ∈ ℤ ≥ M → M ∈ ℤ
19 9 18 syl ⊢ φ → M ∈ ℤ
20 seqm1 ⊢ M ∈ ℤ ∧ K ∈ ℤ ≥ M + 1 → seq M + ˙ F ⁡ K = seq M + ˙ F ⁡ K − 1 + ˙ F ⁡ K
21 19 20 sylan ⊢ φ ∧ K ∈ ℤ ≥ M + 1 → seq M + ˙ F ⁡ K = seq M + ˙ F ⁡ K − 1 + ˙ F ⁡ K
22 7 adantr ⊢ φ ∧ K ∈ ℤ ≥ M + 1 → F ⁡ K = Z
23 22 oveq2d ⊢ φ ∧ K ∈ ℤ ≥ M + 1 → seq M + ˙ F ⁡ K − 1 + ˙ F ⁡ K = seq M + ˙ F ⁡ K − 1 + ˙ Z
24 oveq1 ⊢ x = seq M + ˙ F ⁡ K − 1 → x + ˙ Z = seq M + ˙ F ⁡ K − 1 + ˙ Z
25 24 eqeq1d ⊢ x = seq M + ˙ F ⁡ K − 1 → x + ˙ Z = Z ↔ seq M + ˙ F ⁡ K − 1 + ˙ Z = Z
26 4 ralrimiva ⊢ φ → ∀ x ∈ S x + ˙ Z = Z
27 26 adantr ⊢ φ ∧ K ∈ ℤ ≥ M + 1 → ∀ x ∈ S x + ˙ Z = Z
28 eluzp1m1 ⊢ M ∈ ℤ ∧ K ∈ ℤ ≥ M + 1 → K − 1 ∈ ℤ ≥ M
29 19 28 sylan ⊢ φ ∧ K ∈ ℤ ≥ M + 1 → K − 1 ∈ ℤ ≥ M
30 fzssp1 ⊢ M … K − 1 ⊆ M … K - 1 + 1
31 10 zcnd ⊢ φ → K ∈ ℂ
32 ax-1cn ⊢ 1 ∈ ℂ
33 npcan ⊢ K ∈ ℂ ∧ 1 ∈ ℂ → K - 1 + 1 = K
34 31 32 33 sylancl ⊢ φ → K - 1 + 1 = K
35 34 oveq2d ⊢ φ → M … K - 1 + 1 = M … K
36 30 35 sseqtrid ⊢ φ → M … K − 1 ⊆ M … K
37 elfzuz3 ⊢ K ∈ M … N → N ∈ ℤ ≥ K
38 5 37 syl ⊢ φ → N ∈ ℤ ≥ K
39 fzss2 ⊢ N ∈ ℤ ≥ K → M … K ⊆ M … N
40 38 39 syl ⊢ φ → M … K ⊆ M … N
41 36 40 sstrd ⊢ φ → M … K − 1 ⊆ M … N
42 41 adantr ⊢ φ ∧ K ∈ ℤ ≥ M + 1 → M … K − 1 ⊆ M … N
43 42 sselda ⊢ φ ∧ K ∈ ℤ ≥ M + 1 ∧ x ∈ M … K − 1 → x ∈ M … N
44 2 adantlr ⊢ φ ∧ K ∈ ℤ ≥ M + 1 ∧ x ∈ M … N → F ⁡ x ∈ S
45 43 44 syldan ⊢ φ ∧ K ∈ ℤ ≥ M + 1 ∧ x ∈ M … K − 1 → F ⁡ x ∈ S
46 1 adantlr ⊢ φ ∧ K ∈ ℤ ≥ M + 1 ∧ x ∈ S ∧ y ∈ S → x + ˙ y ∈ S
47 29 45 46 seqcl ⊢ φ ∧ K ∈ ℤ ≥ M + 1 → seq M + ˙ F ⁡ K − 1 ∈ S
48 25 27 47 rspcdva ⊢ φ ∧ K ∈ ℤ ≥ M + 1 → seq M + ˙ F ⁡ K − 1 + ˙ Z = Z
49 23 48 eqtrd ⊢ φ ∧ K ∈ ℤ ≥ M + 1 → seq M + ˙ F ⁡ K − 1 + ˙ F ⁡ K = Z
50 21 49 eqtrd ⊢ φ ∧ K ∈ ℤ ≥ M + 1 → seq M + ˙ F ⁡ K = Z
51 50 ex ⊢ φ → K ∈ ℤ ≥ M + 1 → seq M + ˙ F ⁡ K = Z
52 uzp1 ⊢ K ∈ ℤ ≥ M → K = M ∨ K ∈ ℤ ≥ M + 1
53 9 52 syl ⊢ φ → K = M ∨ K ∈ ℤ ≥ M + 1
54 17 51 53 mpjaod ⊢ φ → seq M + ˙ F ⁡ K = Z
55 54 7 eqtr4d ⊢ φ → seq M + ˙ F ⁡ K = F ⁡ K
56 eqidd ⊢ φ ∧ x ∈ K + 1 … N → F ⁡ x = F ⁡ x
57 9 55 38 56 seqfveq2 ⊢ φ → seq M + ˙ F ⁡ N = seq K + ˙ F ⁡ N
58 fvex ⊢ F ⁡ K ∈ V
59 58 elsn ⊢ F ⁡ K ∈ Z ↔ F ⁡ K = Z
60 7 59 sylibr ⊢ φ → F ⁡ K ∈ Z
61 simprl ⊢ φ ∧ x ∈ Z ∧ y ∈ S → x ∈ Z
62 velsn ⊢ x ∈ Z ↔ x = Z
63 61 62 sylib ⊢ φ ∧ x ∈ Z ∧ y ∈ S → x = Z
64 63 oveq1d ⊢ φ ∧ x ∈ Z ∧ y ∈ S → x + ˙ y = Z + ˙ y
65 oveq2 ⊢ x = y → Z + ˙ x = Z + ˙ y
66 65 eqeq1d ⊢ x = y → Z + ˙ x = Z ↔ Z + ˙ y = Z
67 3 ralrimiva ⊢ φ → ∀ x ∈ S Z + ˙ x = Z
68 67 adantr ⊢ φ ∧ x ∈ Z ∧ y ∈ S → ∀ x ∈ S Z + ˙ x = Z
69 simprr ⊢ φ ∧ x ∈ Z ∧ y ∈ S → y ∈ S
70 66 68 69 rspcdva ⊢ φ ∧ x ∈ Z ∧ y ∈ S → Z + ˙ y = Z
71 64 70 eqtrd ⊢ φ ∧ x ∈ Z ∧ y ∈ S → x + ˙ y = Z
72 ovex ⊢ x + ˙ y ∈ V
73 72 elsn ⊢ x + ˙ y ∈ Z ↔ x + ˙ y = Z
74 71 73 sylibr ⊢ φ ∧ x ∈ Z ∧ y ∈ S → x + ˙ y ∈ Z
75 peano2uz ⊢ K ∈ ℤ ≥ M → K + 1 ∈ ℤ ≥ M
76 9 75 syl ⊢ φ → K + 1 ∈ ℤ ≥ M
77 fzss1 ⊢ K + 1 ∈ ℤ ≥ M → K + 1 … N ⊆ M … N
78 76 77 syl ⊢ φ → K + 1 … N ⊆ M … N
79 78 sselda ⊢ φ ∧ x ∈ K + 1 … N → x ∈ M … N
80 79 2 syldan ⊢ φ ∧ x ∈ K + 1 … N → F ⁡ x ∈ S
81 60 74 38 80 seqcl2 ⊢ φ → seq K + ˙ F ⁡ N ∈ Z
82 elsni ⊢ seq K + ˙ F ⁡ N ∈ Z → seq K + ˙ F ⁡ N = Z
83 81 82 syl ⊢ φ → seq K + ˙ F ⁡ N = Z
84 57 83 eqtrd ⊢ φ → seq M + ˙ F ⁡ N = Z