Metamath Proof Explorer


Theorem setc1ocofval

Description: Composition in the trivial category. (Contributed by Zhi Wang, 22-Oct-2025)

Ref Expression
Hypothesis funcsetc1o.1 ⊢ 1 ˙ = SetCat ⁡ 1 𝑜
Assertion setc1ocofval ⊢ ∅ ∅ ∅ ∅ ∅ ∅ = comp ⁡ 1 ˙

Proof

Step Hyp Ref Expression
1 funcsetc1o.1 ⊢ 1 ˙ = SetCat ⁡ 1 𝑜
2 df-ot ⊢ ∅ ∅ ∅ ∅ ∅ ∅ = ∅ ∅ ∅ ∅ ∅ ∅
3 2 sneqi ⊢ ∅ ∅ ∅ ∅ ∅ ∅ = ∅ ∅ ∅ ∅ ∅ ∅
4 opex ⊢ ∅ ∅ ∈ V
5 0ex ⊢ ∅ ∈ V
6 snex ⊢ ∅ ∅ ∅ ∈ V
7 df1o2 ⊢ 1 𝑜 = ∅
8 7 fveq2i ⊢ SetCat ⁡ 1 𝑜 = SetCat ⁡ ∅
9 1 8 eqtri ⊢ 1 ˙ = SetCat ⁡ ∅
10 snex ⊢ ∅ ∈ V
11 10 a1i ⊢ ⊤ → ∅ ∈ V
12 eqid ⊢ comp ⁡ 1 ˙ = comp ⁡ 1 ˙
13 9 11 12 setccofval ⊢ ⊤ → comp ⁡ 1 ˙ = v ∈ ∅ × ∅ , z ∈ ∅ ⟼ g ∈ z 2 nd ⁡ v , f ∈ 2 nd ⁡ v 1 st ⁡ v ⟼ g ∘ f
14 13 mptru ⊢ comp ⁡ 1 ˙ = v ∈ ∅ × ∅ , z ∈ ∅ ⟼ g ∈ z 2 nd ⁡ v , f ∈ 2 nd ⁡ v 1 st ⁡ v ⟼ g ∘ f
15 5 5 xpsn ⊢ ∅ × ∅ = ∅ ∅
16 eqid ⊢ ∅ = ∅
17 eqid ⊢ g ∈ z 2 nd ⁡ v , f ∈ 2 nd ⁡ v 1 st ⁡ v ⟼ g ∘ f = g ∈ z 2 nd ⁡ v , f ∈ 2 nd ⁡ v 1 st ⁡ v ⟼ g ∘ f
18 15 16 17 mpoeq123i ⊢ v ∈ ∅ × ∅ , z ∈ ∅ ⟼ g ∈ z 2 nd ⁡ v , f ∈ 2 nd ⁡ v 1 st ⁡ v ⟼ g ∘ f = v ∈ ∅ ∅ , z ∈ ∅ ⟼ g ∈ z 2 nd ⁡ v , f ∈ 2 nd ⁡ v 1 st ⁡ v ⟼ g ∘ f
19 14 18 eqtri ⊢ comp ⁡ 1 ˙ = v ∈ ∅ ∅ , z ∈ ∅ ⟼ g ∈ z 2 nd ⁡ v , f ∈ 2 nd ⁡ v 1 st ⁡ v ⟼ g ∘ f
20 5 5 op2ndd ⊢ v = ∅ ∅ → 2 nd ⁡ v = ∅
21 20 oveq2d ⊢ v = ∅ ∅ → z 2 nd ⁡ v = z ∅
22 5 5 op1std ⊢ v = ∅ ∅ → 1 st ⁡ v = ∅
23 20 22 oveq12d ⊢ v = ∅ ∅ → 2 nd ⁡ v 1 st ⁡ v = ∅ ∅
24 0map0sn0 ⊢ ∅ ∅ = ∅
25 23 24 eqtrdi ⊢ v = ∅ ∅ → 2 nd ⁡ v 1 st ⁡ v = ∅
26 eqidd ⊢ v = ∅ ∅ → g ∘ f = g ∘ f
27 21 25 26 mpoeq123dv ⊢ v = ∅ ∅ → g ∈ z 2 nd ⁡ v , f ∈ 2 nd ⁡ v 1 st ⁡ v ⟼ g ∘ f = g ∈ z ∅ , f ∈ ∅ ⟼ g ∘ f
28 oveq1 ⊢ z = ∅ → z ∅ = ∅ ∅
29 28 24 eqtrdi ⊢ z = ∅ → z ∅ = ∅
30 eqidd ⊢ z = ∅ → ∅ = ∅
31 eqidd ⊢ z = ∅ → g ∘ f = g ∘ f
32 29 30 31 mpoeq123dv ⊢ z = ∅ → g ∈ z ∅ , f ∈ ∅ ⟼ g ∘ f = g ∈ ∅ , f ∈ ∅ ⟼ g ∘ f
33 eqid ⊢ g ∈ ∅ , f ∈ ∅ ⟼ g ∘ f = g ∈ ∅ , f ∈ ∅ ⟼ g ∘ f
34 coeq1 ⊢ g = ∅ → g ∘ f = ∅ ∘ f
35 co01 ⊢ ∅ ∘ f = ∅
36 34 35 eqtrdi ⊢ g = ∅ → g ∘ f = ∅
37 eqidd ⊢ f = ∅ → ∅ = ∅
38 33 36 37 mposn ⊢ ∅ ∈ V ∧ ∅ ∈ V ∧ ∅ ∈ V → g ∈ ∅ , f ∈ ∅ ⟼ g ∘ f = ∅ ∅ ∅
39 5 5 5 38 mp3an ⊢ g ∈ ∅ , f ∈ ∅ ⟼ g ∘ f = ∅ ∅ ∅
40 32 39 eqtrdi ⊢ z = ∅ → g ∈ z ∅ , f ∈ ∅ ⟼ g ∘ f = ∅ ∅ ∅
41 df-ot ⊢ ∅ ∅ ∅ = ∅ ∅ ∅
42 41 sneqi ⊢ ∅ ∅ ∅ = ∅ ∅ ∅
43 40 42 eqtr4di ⊢ z = ∅ → g ∈ z ∅ , f ∈ ∅ ⟼ g ∘ f = ∅ ∅ ∅
44 19 27 43 mposn ⊢ ∅ ∅ ∈ V ∧ ∅ ∈ V ∧ ∅ ∅ ∅ ∈ V → comp ⁡ 1 ˙ = ∅ ∅ ∅ ∅ ∅ ∅
45 4 5 6 44 mp3an ⊢ comp ⁡ 1 ˙ = ∅ ∅ ∅ ∅ ∅ ∅
46 3 45 eqtr4i ⊢ ∅ ∅ ∅ ∅ ∅ ∅ = comp ⁡ 1 ˙