Metamath Proof Explorer


Theorem sgn0

Description: The signum of 0 is 0. (Contributed by David A. Wheeler, 15-May-2015)

Ref Expression
Assertion sgn0 ⊢ sgn ⁡ 0 = 0

Proof

Step Hyp Ref Expression
1 0xr ⊢ 0 ∈ ℝ *
2 sgnval ⊢ 0 ∈ ℝ * → sgn ⁡ 0 = if 0 = 0 0 if 0 < 0 − 1 1
3 1 2 ax-mp ⊢ sgn ⁡ 0 = if 0 = 0 0 if 0 < 0 − 1 1
4 eqid ⊢ 0 = 0
5 4 iftruei ⊢ if 0 = 0 0 if 0 < 0 − 1 1 = 0
6 3 5 eqtri ⊢ sgn ⁡ 0 = 0