Metamath Proof Explorer


Theorem sgn1

Description: The signum of 1 is 1. (Contributed by David A. Wheeler, 26-Jun-2016)

Ref Expression
Assertion sgn1 ⊢ sgn ⁡ 1 = 1

Proof

Step Hyp Ref Expression
1 1xr ⊢ 1 ∈ ℝ *
2 0lt1 ⊢ 0 < 1
3 sgnp ⊢ 1 ∈ ℝ * ∧ 0 < 1 → sgn ⁡ 1 = 1
4 1 2 3 mp2an ⊢ sgn ⁡ 1 = 1