Metamath Proof Explorer


Theorem sinasin

Description: The arcsine function is an inverse to sin . This is the main property that justifies the notation arcsin or sin ^ -u 1 . Because sin is not an injection, the other converse identity asinsin is only true under limited circumstances. (Contributed by Mario Carneiro, 1-Apr-2015)

Ref Expression
Assertion sinasin ⊢ A ∈ ℂ → sin ⁡ arcsin ⁡ A = A

Proof

Step Hyp Ref Expression
1 asincl ⊢ A ∈ ℂ → arcsin ⁡ A ∈ ℂ
2 sinval ⊢ arcsin ⁡ A ∈ ℂ → sin ⁡ arcsin ⁡ A = e i ⁢ arcsin ⁡ A − e − i ⁢ arcsin ⁡ A 2 ⁢ i
3 1 2 syl ⊢ A ∈ ℂ → sin ⁡ arcsin ⁡ A = e i ⁢ arcsin ⁡ A − e − i ⁢ arcsin ⁡ A 2 ⁢ i
4 ax-icn ⊢ i ∈ ℂ
5 mulcl ⊢ i ∈ ℂ ∧ A ∈ ℂ → i ⁢ A ∈ ℂ
6 4 5 mpan ⊢ A ∈ ℂ → i ⁢ A ∈ ℂ
7 6 negcld ⊢ A ∈ ℂ → − i ⁢ A ∈ ℂ
8 ax-1cn ⊢ 1 ∈ ℂ
9 sqcl ⊢ A ∈ ℂ → A 2 ∈ ℂ
10 subcl ⊢ 1 ∈ ℂ ∧ A 2 ∈ ℂ → 1 − A 2 ∈ ℂ
11 8 9 10 sylancr ⊢ A ∈ ℂ → 1 − A 2 ∈ ℂ
12 11 sqrtcld ⊢ A ∈ ℂ → 1 − A 2 ∈ ℂ
13 6 7 12 pnpcan2d ⊢ A ∈ ℂ → i ⁢ A + 1 − A 2 - - i ⁢ A + 1 − A 2 = i ⁢ A − − i ⁢ A
14 efiasin ⊢ A ∈ ℂ → e i ⁢ arcsin ⁡ A = i ⁢ A + 1 − A 2
15 mulneg12 ⊢ i ∈ ℂ ∧ arcsin ⁡ A ∈ ℂ → − i ⁢ arcsin ⁡ A = i ⁢ − arcsin ⁡ A
16 4 1 15 sylancr ⊢ A ∈ ℂ → − i ⁢ arcsin ⁡ A = i ⁢ − arcsin ⁡ A
17 asinneg ⊢ A ∈ ℂ → arcsin ⁡ − A = − arcsin ⁡ A
18 17 oveq2d ⊢ A ∈ ℂ → i ⁢ arcsin ⁡ − A = i ⁢ − arcsin ⁡ A
19 16 18 eqtr4d ⊢ A ∈ ℂ → − i ⁢ arcsin ⁡ A = i ⁢ arcsin ⁡ − A
20 19 fveq2d ⊢ A ∈ ℂ → e − i ⁢ arcsin ⁡ A = e i ⁢ arcsin ⁡ − A
21 negcl ⊢ A ∈ ℂ → − A ∈ ℂ
22 efiasin ⊢ − A ∈ ℂ → e i ⁢ arcsin ⁡ − A = i ⁢ − A + 1 − − A 2
23 21 22 syl ⊢ A ∈ ℂ → e i ⁢ arcsin ⁡ − A = i ⁢ − A + 1 − − A 2
24 mulneg2 ⊢ i ∈ ℂ ∧ A ∈ ℂ → i ⁢ − A = − i ⁢ A
25 4 24 mpan ⊢ A ∈ ℂ → i ⁢ − A = − i ⁢ A
26 sqneg ⊢ A ∈ ℂ → − A 2 = A 2
27 26 oveq2d ⊢ A ∈ ℂ → 1 − − A 2 = 1 − A 2
28 27 fveq2d ⊢ A ∈ ℂ → 1 − − A 2 = 1 − A 2
29 25 28 oveq12d ⊢ A ∈ ℂ → i ⁢ − A + 1 − − A 2 = - i ⁢ A + 1 − A 2
30 20 23 29 3eqtrd ⊢ A ∈ ℂ → e − i ⁢ arcsin ⁡ A = - i ⁢ A + 1 − A 2
31 14 30 oveq12d ⊢ A ∈ ℂ → e i ⁢ arcsin ⁡ A − e − i ⁢ arcsin ⁡ A = i ⁢ A + 1 − A 2 - - i ⁢ A + 1 − A 2
32 6 2timesd ⊢ A ∈ ℂ → 2 ⁢ i ⁢ A = i ⁢ A + i ⁢ A
33 2cn ⊢ 2 ∈ ℂ
34 mulass ⊢ 2 ∈ ℂ ∧ i ∈ ℂ ∧ A ∈ ℂ → 2 ⁢ i ⁢ A = 2 ⁢ i ⁢ A
35 33 4 34 mp3an12 ⊢ A ∈ ℂ → 2 ⁢ i ⁢ A = 2 ⁢ i ⁢ A
36 6 6 subnegd ⊢ A ∈ ℂ → i ⁢ A − − i ⁢ A = i ⁢ A + i ⁢ A
37 32 35 36 3eqtr4d ⊢ A ∈ ℂ → 2 ⁢ i ⁢ A = i ⁢ A − − i ⁢ A
38 13 31 37 3eqtr4d ⊢ A ∈ ℂ → e i ⁢ arcsin ⁡ A − e − i ⁢ arcsin ⁡ A = 2 ⁢ i ⁢ A
39 mulcl ⊢ i ∈ ℂ ∧ arcsin ⁡ A ∈ ℂ → i ⁢ arcsin ⁡ A ∈ ℂ
40 4 1 39 sylancr ⊢ A ∈ ℂ → i ⁢ arcsin ⁡ A ∈ ℂ
41 efcl ⊢ i ⁢ arcsin ⁡ A ∈ ℂ → e i ⁢ arcsin ⁡ A ∈ ℂ
42 40 41 syl ⊢ A ∈ ℂ → e i ⁢ arcsin ⁡ A ∈ ℂ
43 negicn ⊢ − i ∈ ℂ
44 mulcl ⊢ − i ∈ ℂ ∧ arcsin ⁡ A ∈ ℂ → − i ⁢ arcsin ⁡ A ∈ ℂ
45 43 1 44 sylancr ⊢ A ∈ ℂ → − i ⁢ arcsin ⁡ A ∈ ℂ
46 efcl ⊢ − i ⁢ arcsin ⁡ A ∈ ℂ → e − i ⁢ arcsin ⁡ A ∈ ℂ
47 45 46 syl ⊢ A ∈ ℂ → e − i ⁢ arcsin ⁡ A ∈ ℂ
48 42 47 subcld ⊢ A ∈ ℂ → e i ⁢ arcsin ⁡ A − e − i ⁢ arcsin ⁡ A ∈ ℂ
49 id ⊢ A ∈ ℂ → A ∈ ℂ
50 2mulicn ⊢ 2 ⁢ i ∈ ℂ
51 50 a1i ⊢ A ∈ ℂ → 2 ⁢ i ∈ ℂ
52 2muline0 ⊢ 2 ⁢ i ≠ 0
53 52 a1i ⊢ A ∈ ℂ → 2 ⁢ i ≠ 0
54 48 49 51 53 divmul2d ⊢ A ∈ ℂ → e i ⁢ arcsin ⁡ A − e − i ⁢ arcsin ⁡ A 2 ⁢ i = A ↔ e i ⁢ arcsin ⁡ A − e − i ⁢ arcsin ⁡ A = 2 ⁢ i ⁢ A
55 38 54 mpbird ⊢ A ∈ ℂ → e i ⁢ arcsin ⁡ A − e − i ⁢ arcsin ⁡ A 2 ⁢ i = A
56 3 55 eqtrd ⊢ A ∈ ℂ → sin ⁡ arcsin ⁡ A = A