Metamath Proof Explorer


Theorem speivw

Description: Version of spei with a disjoint variable condition, which does not require ax-13 (neither ax-7 nor ax-12 ). (Contributed by BJ, 31-May-2019)

Ref Expression
Hypotheses speivw.1 ⊢ x = y → φ ↔ ψ
speivw.2 ⊢ ψ
Assertion speivw ⊢ ∃ x φ

Proof

Step Hyp Ref Expression
1 speivw.1 ⊢ x = y → φ ↔ ψ
2 speivw.2 ⊢ ψ
3 1 biimprd ⊢ x = y → ψ → φ
4 3 2 speiv ⊢ ∃ x φ