Metamath Proof Explorer


Theorem spv

Description: Specialization, using implicit substitution. Usage of this theorem is discouraged because it depends on ax-13 . Use the weaker spvv if possible. (Contributed by NM, 30-Aug-1993) (New usage is discouraged.)

Ref Expression
Hypothesis spv.1 x = y φ ψ
Assertion spv x φ ψ

Proof

Step Hyp Ref Expression
1 spv.1 x = y φ ψ
2 1 biimpd x = y φ ψ
3 2 spimv x φ ψ