Metamath Proof Explorer


Theorem sqdivd

Description: Distribution of squaring over division. (Contributed by Mario Carneiro, 28-May-2016)

Ref Expression
Hypotheses expcld.1 ⊢ φ → A ∈ ℂ
mulexpd.2 ⊢ φ → B ∈ ℂ
sqdivd.3 ⊢ φ → B ≠ 0
Assertion sqdivd ⊢ φ → A B 2 = A 2 B 2

Proof

Step Hyp Ref Expression
1 expcld.1 ⊢ φ → A ∈ ℂ
2 mulexpd.2 ⊢ φ → B ∈ ℂ
3 sqdivd.3 ⊢ φ → B ≠ 0
4 sqdiv ⊢ A ∈ ℂ ∧ B ∈ ℂ ∧ B ≠ 0 → A B 2 = A 2 B 2
5 1 2 3 4 syl3anc ⊢ φ → A B 2 = A 2 B 2