Metamath Proof Explorer


Theorem sqrt2irr0

Description: The square root of 2 is an irrational number. (Contributed by AV, 23-Dec-2022)

Ref Expression
Assertion sqrt2irr0 ⊢ 2 ∈ ℝ ∖ ℚ

Proof

Step Hyp Ref Expression
1 sqrt2irr ⊢ 2 ∉ ℚ
2 sqrt2re ⊢ 2 ∈ ℝ
3 2 a1i ⊢ 2 ∉ ℚ → 2 ∈ ℝ
4 df-nel ⊢ 2 ∉ ℚ ↔ ¬ 2 ∈ ℚ
5 4 biimpi ⊢ 2 ∉ ℚ → ¬ 2 ∈ ℚ
6 3 5 eldifd ⊢ 2 ∉ ℚ → 2 ∈ ℝ ∖ ℚ
7 1 6 ax-mp ⊢ 2 ∈ ℝ ∖ ℚ