Metamath Proof Explorer


Theorem sqrt9

Description: The square root of 9 is 3. (Contributed by NM, 11-May-2004)

Ref Expression
Assertion sqrt9 ⊢ 9 = 3

Proof

Step Hyp Ref Expression
1 sq3 ⊢ 3 2 = 9
2 1 fveq2i ⊢ 3 2 = 9
3 3re ⊢ 3 ∈ ℝ
4 0re ⊢ 0 ∈ ℝ
5 3pos ⊢ 0 < 3
6 4 3 5 ltleii ⊢ 0 ≤ 3
7 sqrtsq ⊢ 3 ∈ ℝ ∧ 0 ≤ 3 → 3 2 = 3
8 3 6 7 mp2an ⊢ 3 2 = 3
9 2 8 eqtr3i ⊢ 9 = 3