Metamath Proof Explorer


Theorem sqrtcl

Description: Closure of the square root function over the complex numbers. (Contributed by Mario Carneiro, 10-Jul-2013)

Ref Expression
Assertion sqrtcl ⊢ A ∈ ℂ → A ∈ ℂ

Proof

Step Hyp Ref Expression
1 sqrtval ⊢ A ∈ ℂ → A = ι x ∈ ℂ | x 2 = A ∧ 0 ≤ ℜ ⁡ x ∧ i ⁢ x ∉ ℝ +
2 sqreu ⊢ A ∈ ℂ → ∃! x ∈ ℂ x 2 = A ∧ 0 ≤ ℜ ⁡ x ∧ i ⁢ x ∉ ℝ +
3 riotacl ⊢ ∃! x ∈ ℂ x 2 = A ∧ 0 ≤ ℜ ⁡ x ∧ i ⁢ x ∉ ℝ + → ι x ∈ ℂ | x 2 = A ∧ 0 ≤ ℜ ⁡ x ∧ i ⁢ x ∉ ℝ + ∈ ℂ
4 2 3 syl ⊢ A ∈ ℂ → ι x ∈ ℂ | x 2 = A ∧ 0 ≤ ℜ ⁡ x ∧ i ⁢ x ∉ ℝ + ∈ ℂ
5 1 4 eqeltrd ⊢ A ∈ ℂ → A ∈ ℂ