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sqvald
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sqcld
Metamath Proof Explorer
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Theorem
sqvald
Description:
Value of square. Inference version.
(Contributed by
Mario Carneiro
, 28-May-2016)
Ref
Expression
Hypothesis
expcld.1
⊢
φ
→
A
∈
ℂ
Assertion
sqvald
⊢
φ
→
A
2
=
A
⁢
A
Proof
Step
Hyp
Ref
Expression
1
expcld.1
⊢
φ
→
A
∈
ℂ
2
sqval
⊢
A
∈
ℂ
→
A
2
=
A
⁢
A
3
1
2
syl
⊢
φ
→
A
2
=
A
⁢
A