Metamath Proof Explorer


Theorem srhmsubclem1

Description: Lemma 1 for srhmsubc . (Contributed by AV, 19-Feb-2020)

Ref Expression
Hypotheses srhmsubc.s ⊢ ∀ r ∈ S r ∈ Ring
srhmsubc.c ⊢ C = U ∩ S
Assertion srhmsubclem1 ⊢ X ∈ C → X ∈ U ∩ Ring

Proof

Step Hyp Ref Expression
1 srhmsubc.s ⊢ ∀ r ∈ S r ∈ Ring
2 srhmsubc.c ⊢ C = U ∩ S
3 eleq1 ⊢ r = X → r ∈ Ring ↔ X ∈ Ring
4 3 1 vtoclri ⊢ X ∈ S → X ∈ Ring
5 4 anim2i ⊢ X ∈ U ∧ X ∈ S → X ∈ U ∧ X ∈ Ring
6 2 elin2 ⊢ X ∈ C ↔ X ∈ U ∧ X ∈ S
7 elin ⊢ X ∈ U ∩ Ring ↔ X ∈ U ∧ X ∈ Ring
8 5 6 7 3imtr4i ⊢ X ∈ C → X ∈ U ∩ Ring