Metamath Proof Explorer
Description: An equality inference for the subclass relationship. (Contributed by NM, 31-May-1999) (Proof shortened by Eric Schmidt, 26-Jan-2007)
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Ref |
Expression |
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Hypotheses |
sseq1i.1 |
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sseq12i.2 |
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Assertion |
sseq12i |
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Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
sseq1i.1 |
|
| 2 |
|
sseq12i.2 |
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| 3 |
|
sseq12 |
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| 4 |
1 2 3
|
mp2an |
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