Metamath Proof Explorer


Theorem ssexnelpss

Description: If there is an element of a class which is not contained in a subclass, the subclass is a proper subclass. (Contributed by AV, 29-Jan-2020)

Ref Expression
Assertion ssexnelpss A B x B x A A B

Proof

Step Hyp Ref Expression
1 df-nel x A ¬ x A
2 ssnelpss A B x B ¬ x A A B
3 2 expdimp A B x B ¬ x A A B
4 1 3 syl5bi A B x B x A A B
5 4 rexlimdva A B x B x A A B
6 5 imp A B x B x A A B