Metamath Proof Explorer


Theorem ssin0

Description: If two classes are disjoint, two respective subclasses are disjoint. (Contributed by Glauco Siliprandi, 17-Aug-2020)

Ref Expression
Assertion ssin0 ⊢ A ∩ B = ∅ ∧ C ⊆ A ∧ D ⊆ B → C ∩ D = ∅

Proof

Step Hyp Ref Expression
1 ss2in ⊢ C ⊆ A ∧ D ⊆ B → C ∩ D ⊆ A ∩ B
2 1 3adant1 ⊢ A ∩ B = ∅ ∧ C ⊆ A ∧ D ⊆ B → C ∩ D ⊆ A ∩ B
3 eqimss ⊢ A ∩ B = ∅ → A ∩ B ⊆ ∅
4 3 3ad2ant1 ⊢ A ∩ B = ∅ ∧ C ⊆ A ∧ D ⊆ B → A ∩ B ⊆ ∅
5 2 4 sstrd ⊢ A ∩ B = ∅ ∧ C ⊆ A ∧ D ⊆ B → C ∩ D ⊆ ∅
6 ss0 ⊢ C ∩ D ⊆ ∅ → C ∩ D = ∅
7 5 6 syl ⊢ A ∩ B = ∅ ∧ C ⊆ A ∧ D ⊆ B → C ∩ D = ∅