Metamath Proof Explorer


Theorem sub1cncfd

Description: Subtracting a constant is a continuous function. (Contributed by Glauco Siliprandi, 8-Apr-2021)

Ref Expression
Hypotheses sub1cncfd.1 ⊢ φ → A ∈ ℂ
sub1cncfd.2 ⊢ F = x ∈ ℂ ⟼ x − A
Assertion sub1cncfd ⊢ φ → F : ℂ ⟶cn ℂ

Proof

Step Hyp Ref Expression
1 sub1cncfd.1 ⊢ φ → A ∈ ℂ
2 sub1cncfd.2 ⊢ F = x ∈ ℂ ⟼ x − A
3 ssid ⊢ ℂ ⊆ ℂ
4 cncfmptid ⊢ ℂ ⊆ ℂ ∧ ℂ ⊆ ℂ → x ∈ ℂ ⟼ x : ℂ ⟶cn ℂ
5 3 3 4 mp2an ⊢ x ∈ ℂ ⟼ x : ℂ ⟶cn ℂ
6 5 a1i ⊢ φ → x ∈ ℂ ⟼ x : ℂ ⟶cn ℂ
7 3 a1i ⊢ φ → ℂ ⊆ ℂ
8 cncfmptc ⊢ A ∈ ℂ ∧ ℂ ⊆ ℂ ∧ ℂ ⊆ ℂ → x ∈ ℂ ⟼ A : ℂ ⟶cn ℂ
9 1 7 7 8 syl3anc ⊢ φ → x ∈ ℂ ⟼ A : ℂ ⟶cn ℂ
10 6 9 subcncf ⊢ φ → x ∈ ℂ ⟼ x − A : ℂ ⟶cn ℂ
11 2 10 eqeltrid ⊢ φ → F : ℂ ⟶cn ℂ