Metamath Proof Explorer


Theorem sub2cncfd

Description: Subtraction from a constant is a continuous function. (Contributed by Glauco Siliprandi, 8-Apr-2021)

Ref Expression
Hypotheses sub2cncfd.1 ⊢ φ → A ∈ ℂ
sub2cncfd.2 ⊢ F = x ∈ ℂ ⟼ A − x
Assertion sub2cncfd ⊢ φ → F : ℂ ⟶cn ℂ

Proof

Step Hyp Ref Expression
1 sub2cncfd.1 ⊢ φ → A ∈ ℂ
2 sub2cncfd.2 ⊢ F = x ∈ ℂ ⟼ A − x
3 ssid ⊢ ℂ ⊆ ℂ
4 3 a1i ⊢ φ → ℂ ⊆ ℂ
5 cncfmptc ⊢ A ∈ ℂ ∧ ℂ ⊆ ℂ ∧ ℂ ⊆ ℂ → x ∈ ℂ ⟼ A : ℂ ⟶cn ℂ
6 1 4 4 5 syl3anc ⊢ φ → x ∈ ℂ ⟼ A : ℂ ⟶cn ℂ
7 cncfmptid ⊢ ℂ ⊆ ℂ ∧ ℂ ⊆ ℂ → x ∈ ℂ ⟼ x : ℂ ⟶cn ℂ
8 3 3 7 mp2an ⊢ x ∈ ℂ ⟼ x : ℂ ⟶cn ℂ
9 8 a1i ⊢ φ → x ∈ ℂ ⟼ x : ℂ ⟶cn ℂ
10 6 9 subcncf ⊢ φ → x ∈ ℂ ⟼ A − x : ℂ ⟶cn ℂ
11 2 10 eqeltrid ⊢ φ → F : ℂ ⟶cn ℂ