Metamath Proof Explorer


Theorem subexsub

Description: A subtraction law: Exchanging the subtrahend and the result of the subtraction. (Contributed by BJ, 6-Jun-2019)

Ref Expression
Hypotheses addlsub.a φ A
addlsub.b φ B
addlsub.c φ C
Assertion subexsub φ A = C B B = C A

Proof

Step Hyp Ref Expression
1 addlsub.a φ A
2 addlsub.b φ B
3 addlsub.c φ C
4 1 2 3 addlsub φ A + B = C A = C B
5 1 2 3 addrsub φ A + B = C B = C A
6 4 5 bitr3d φ A = C B B = C A