Metamath Proof Explorer


Theorem subfac1

Description: The subfactorial at one. (Contributed by Mario Carneiro, 19-Jan-2015)

Ref Expression
Hypotheses derang.d ⊢ D = x ∈ Fin ⟼ f | f : x ⟶ 1-1 onto x ∧ ∀ y ∈ x f ⁡ y ≠ y
subfac.n ⊢ S = n ∈ ℕ 0 ⟼ D ⁡ 1 … n
Assertion subfac1 ⊢ S ⁡ 1 = 0

Proof

Step Hyp Ref Expression
1 derang.d ⊢ D = x ∈ Fin ⟼ f | f : x ⟶ 1-1 onto x ∧ ∀ y ∈ x f ⁡ y ≠ y
2 subfac.n ⊢ S = n ∈ ℕ 0 ⟼ D ⁡ 1 … n
3 1nn0 ⊢ 1 ∈ ℕ 0
4 1 2 subfacval ⊢ 1 ∈ ℕ 0 → S ⁡ 1 = D ⁡ 1 … 1
5 3 4 ax-mp ⊢ S ⁡ 1 = D ⁡ 1 … 1
6 1z ⊢ 1 ∈ ℤ
7 fzsn ⊢ 1 ∈ ℤ → 1 … 1 = 1
8 6 7 ax-mp ⊢ 1 … 1 = 1
9 8 fveq2i ⊢ D ⁡ 1 … 1 = D ⁡ 1
10 1 derangsn ⊢ 1 ∈ ℕ 0 → D ⁡ 1 = 0
11 3 10 ax-mp ⊢ D ⁡ 1 = 0
12 5 9 11 3eqtri ⊢ S ⁡ 1 = 0