Metamath Proof Explorer


Theorem subfacval3

Description: Another closed form expression for the subfactorial. The expression |_( x + 1 / 2 ) is a way of saying "rounded to the nearest integer". (Contributed by Mario Carneiro, 23-Jan-2015)

Ref Expression
Hypotheses derang.d ⊢ D = x ∈ Fin ⟼ f | f : x ⟶ 1-1 onto x ∧ ∀ y ∈ x f ⁡ y ≠ y
subfac.n ⊢ S = n ∈ ℕ 0 ⟼ D ⁡ 1 … n
Assertion subfacval3 ⊢ N ∈ ℕ → S ⁡ N = N ! e + 1 2

Proof

Step Hyp Ref Expression
1 derang.d ⊢ D = x ∈ Fin ⟼ f | f : x ⟶ 1-1 onto x ∧ ∀ y ∈ x f ⁡ y ≠ y
2 subfac.n ⊢ S = n ∈ ℕ 0 ⟼ D ⁡ 1 … n
3 nnnn0 ⊢ N ∈ ℕ → N ∈ ℕ 0
4 1 2 subfacf ⊢ S : ℕ 0 ⟶ ℕ 0
5 4 ffvelcdmi ⊢ N ∈ ℕ 0 → S ⁡ N ∈ ℕ 0
6 3 5 syl ⊢ N ∈ ℕ → S ⁡ N ∈ ℕ 0
7 6 nn0zd ⊢ N ∈ ℕ → S ⁡ N ∈ ℤ
8 7 zred ⊢ N ∈ ℕ → S ⁡ N ∈ ℝ
9 faccl ⊢ N ∈ ℕ 0 → N ! ∈ ℕ
10 3 9 syl ⊢ N ∈ ℕ → N ! ∈ ℕ
11 10 nnred ⊢ N ∈ ℕ → N ! ∈ ℝ
12 epr ⊢ e ∈ ℝ +
13 rerpdivcl ⊢ N ! ∈ ℝ ∧ e ∈ ℝ + → N ! e ∈ ℝ
14 11 12 13 sylancl ⊢ N ∈ ℕ → N ! e ∈ ℝ
15 halfre ⊢ 1 2 ∈ ℝ
16 readdcl ⊢ N ! e ∈ ℝ ∧ 1 2 ∈ ℝ → N ! e + 1 2 ∈ ℝ
17 14 15 16 sylancl ⊢ N ∈ ℕ → N ! e + 1 2 ∈ ℝ
18 elnn1uz2 ⊢ N ∈ ℕ ↔ N = 1 ∨ N ∈ ℤ ≥ 2
19 fveq2 ⊢ N = 1 → N ! = 1 !
20 fac1 ⊢ 1 ! = 1
21 19 20 eqtrdi ⊢ N = 1 → N ! = 1
22 21 oveq1d ⊢ N = 1 → N ! e = 1 e
23 fveq2 ⊢ N = 1 → S ⁡ N = S ⁡ 1
24 1 2 subfac1 ⊢ S ⁡ 1 = 0
25 23 24 eqtrdi ⊢ N = 1 → S ⁡ N = 0
26 22 25 oveq12d ⊢ N = 1 → N ! e − S ⁡ N = 1 e − 0
27 rpreccl ⊢ e ∈ ℝ + → 1 e ∈ ℝ +
28 12 27 ax-mp ⊢ 1 e ∈ ℝ +
29 rpre ⊢ 1 e ∈ ℝ + → 1 e ∈ ℝ
30 28 29 ax-mp ⊢ 1 e ∈ ℝ
31 30 recni ⊢ 1 e ∈ ℂ
32 31 subid1i ⊢ 1 e − 0 = 1 e
33 26 32 eqtrdi ⊢ N = 1 → N ! e − S ⁡ N = 1 e
34 33 fveq2d ⊢ N = 1 → N ! e − S ⁡ N = 1 e
35 rpge0 ⊢ 1 e ∈ ℝ + → 0 ≤ 1 e
36 28 35 ax-mp ⊢ 0 ≤ 1 e
37 absid ⊢ 1 e ∈ ℝ ∧ 0 ≤ 1 e → 1 e = 1 e
38 30 36 37 mp2an ⊢ 1 e = 1 e
39 34 38 eqtrdi ⊢ N = 1 → N ! e − S ⁡ N = 1 e
40 egt2lt3 ⊢ 2 < e ∧ e < 3
41 40 simpli ⊢ 2 < e
42 2re ⊢ 2 ∈ ℝ
43 ere ⊢ e ∈ ℝ
44 2pos ⊢ 0 < 2
45 epos ⊢ 0 < e
46 42 43 44 45 ltrecii ⊢ 2 < e ↔ 1 e < 1 2
47 41 46 mpbi ⊢ 1 e < 1 2
48 39 47 eqbrtrdi ⊢ N = 1 → N ! e − S ⁡ N < 1 2
49 eluz2nn ⊢ N ∈ ℤ ≥ 2 → N ∈ ℕ
50 14 8 resubcld ⊢ N ∈ ℕ → N ! e − S ⁡ N ∈ ℝ
51 50 recnd ⊢ N ∈ ℕ → N ! e − S ⁡ N ∈ ℂ
52 49 51 syl ⊢ N ∈ ℤ ≥ 2 → N ! e − S ⁡ N ∈ ℂ
53 52 abscld ⊢ N ∈ ℤ ≥ 2 → N ! e − S ⁡ N ∈ ℝ
54 49 nnrecred ⊢ N ∈ ℤ ≥ 2 → 1 N ∈ ℝ
55 15 a1i ⊢ N ∈ ℤ ≥ 2 → 1 2 ∈ ℝ
56 1 2 subfaclim ⊢ N ∈ ℕ → N ! e − S ⁡ N < 1 N
57 49 56 syl ⊢ N ∈ ℤ ≥ 2 → N ! e − S ⁡ N < 1 N
58 eluzle ⊢ N ∈ ℤ ≥ 2 → 2 ≤ N
59 nnre ⊢ N ∈ ℕ → N ∈ ℝ
60 nngt0 ⊢ N ∈ ℕ → 0 < N
61 lerec ⊢ 2 ∈ ℝ ∧ 0 < 2 ∧ N ∈ ℝ ∧ 0 < N → 2 ≤ N ↔ 1 N ≤ 1 2
62 42 44 61 mpanl12 ⊢ N ∈ ℝ ∧ 0 < N → 2 ≤ N ↔ 1 N ≤ 1 2
63 59 60 62 syl2anc ⊢ N ∈ ℕ → 2 ≤ N ↔ 1 N ≤ 1 2
64 49 63 syl ⊢ N ∈ ℤ ≥ 2 → 2 ≤ N ↔ 1 N ≤ 1 2
65 58 64 mpbid ⊢ N ∈ ℤ ≥ 2 → 1 N ≤ 1 2
66 53 54 55 57 65 ltletrd ⊢ N ∈ ℤ ≥ 2 → N ! e − S ⁡ N < 1 2
67 48 66 jaoi ⊢ N = 1 ∨ N ∈ ℤ ≥ 2 → N ! e − S ⁡ N < 1 2
68 18 67 sylbi ⊢ N ∈ ℕ → N ! e − S ⁡ N < 1 2
69 15 a1i ⊢ N ∈ ℕ → 1 2 ∈ ℝ
70 14 8 69 absdifltd ⊢ N ∈ ℕ → N ! e − S ⁡ N < 1 2 ↔ S ⁡ N − 1 2 < N ! e ∧ N ! e < S ⁡ N + 1 2
71 68 70 mpbid ⊢ N ∈ ℕ → S ⁡ N − 1 2 < N ! e ∧ N ! e < S ⁡ N + 1 2
72 71 simpld ⊢ N ∈ ℕ → S ⁡ N − 1 2 < N ! e
73 8 69 14 ltsubaddd ⊢ N ∈ ℕ → S ⁡ N − 1 2 < N ! e ↔ S ⁡ N < N ! e + 1 2
74 72 73 mpbid ⊢ N ∈ ℕ → S ⁡ N < N ! e + 1 2
75 8 17 74 ltled ⊢ N ∈ ℕ → S ⁡ N ≤ N ! e + 1 2
76 readdcl ⊢ S ⁡ N ∈ ℝ ∧ 1 2 ∈ ℝ → S ⁡ N + 1 2 ∈ ℝ
77 8 15 76 sylancl ⊢ N ∈ ℕ → S ⁡ N + 1 2 ∈ ℝ
78 71 simprd ⊢ N ∈ ℕ → N ! e < S ⁡ N + 1 2
79 14 77 69 78 ltadd1dd ⊢ N ∈ ℕ → N ! e + 1 2 < S ⁡ N + 1 2 + 1 2
80 8 recnd ⊢ N ∈ ℕ → S ⁡ N ∈ ℂ
81 69 recnd ⊢ N ∈ ℕ → 1 2 ∈ ℂ
82 80 81 81 addassd ⊢ N ∈ ℕ → S ⁡ N + 1 2 + 1 2 = S ⁡ N + 1 2 + 1 2
83 ax-1cn ⊢ 1 ∈ ℂ
84 2halves ⊢ 1 ∈ ℂ → 1 2 + 1 2 = 1
85 83 84 ax-mp ⊢ 1 2 + 1 2 = 1
86 85 oveq2i ⊢ S ⁡ N + 1 2 + 1 2 = S ⁡ N + 1
87 82 86 eqtrdi ⊢ N ∈ ℕ → S ⁡ N + 1 2 + 1 2 = S ⁡ N + 1
88 79 87 breqtrd ⊢ N ∈ ℕ → N ! e + 1 2 < S ⁡ N + 1
89 flbi ⊢ N ! e + 1 2 ∈ ℝ ∧ S ⁡ N ∈ ℤ → N ! e + 1 2 = S ⁡ N ↔ S ⁡ N ≤ N ! e + 1 2 ∧ N ! e + 1 2 < S ⁡ N + 1
90 17 7 89 syl2anc ⊢ N ∈ ℕ → N ! e + 1 2 = S ⁡ N ↔ S ⁡ N ≤ N ! e + 1 2 ∧ N ! e + 1 2 < S ⁡ N + 1
91 75 88 90 mpbir2and ⊢ N ∈ ℕ → N ! e + 1 2 = S ⁡ N
92 91 eqcomd ⊢ N ∈ ℕ → S ⁡ N = N ! e + 1 2