Metamath Proof Explorer


Theorem subgcld

Description: A subgroup is closed under group operation. (Contributed by Thierry Arnoux, 3-Jun-2025)

Ref Expression
Hypotheses subgcld.1 ⊢ + ˙ = + G
subgcld.2 ⊢ φ → S ∈ SubGrp ⁡ G
subgcld.3 ⊢ φ → X ∈ S
subgcld.4 ⊢ φ → Y ∈ S
Assertion subgcld ⊢ φ → X + ˙ Y ∈ S

Proof

Step Hyp Ref Expression
1 subgcld.1 ⊢ + ˙ = + G
2 subgcld.2 ⊢ φ → S ∈ SubGrp ⁡ G
3 subgcld.3 ⊢ φ → X ∈ S
4 subgcld.4 ⊢ φ → Y ∈ S
5 1 subgcl ⊢ S ∈ SubGrp ⁡ G ∧ X ∈ S ∧ Y ∈ S → X + ˙ Y ∈ S
6 2 3 4 5 syl3anc ⊢ φ → X + ˙ Y ∈ S