Metamath Proof Explorer


Theorem subgss

Description: A subgroup is a subset. (Contributed by Mario Carneiro, 2-Dec-2014)

Ref Expression
Hypothesis issubg.b ⊢ B = Base G
Assertion subgss ⊢ S ∈ SubGrp ⁡ G → S ⊆ B

Proof

Step Hyp Ref Expression
1 issubg.b ⊢ B = Base G
2 1 issubg ⊢ S ∈ SubGrp ⁡ G ↔ G ∈ Grp ∧ S ⊆ B ∧ G ↾ 𝑠 S ∈ Grp
3 2 simp2bi ⊢ S ∈ SubGrp ⁡ G → S ⊆ B