Metamath Proof Explorer


Theorem submrcl

Description: Reverse closure for submonoids. (Contributed by Mario Carneiro, 7-Mar-2015)

Ref Expression
Assertion submrcl S SubMnd M M Mnd

Proof

Step Hyp Ref Expression
1 df-submnd SubMnd = s Mnd t 𝒫 Base s | 0 s t x t y t x + s y t
2 1 mptrcl S SubMnd M M Mnd