Metamath Proof Explorer


Theorem subrg0

Description: A subring always has the same additive identity. (Contributed by Stefan O'Rear, 27-Nov-2014)

Ref Expression
Hypotheses subrg0.1 ⊢ S = R ↾ 𝑠 A
subrg0.2 ⊢ 0 ˙ = 0 R
Assertion subrg0 ⊢ A ∈ SubRing ⁡ R → 0 ˙ = 0 S

Proof

Step Hyp Ref Expression
1 subrg0.1 ⊢ S = R ↾ 𝑠 A
2 subrg0.2 ⊢ 0 ˙ = 0 R
3 subrgsubg ⊢ A ∈ SubRing ⁡ R → A ∈ SubGrp ⁡ R
4 1 2 subg0 ⊢ A ∈ SubGrp ⁡ R → 0 ˙ = 0 S
5 3 4 syl ⊢ A ∈ SubRing ⁡ R → 0 ˙ = 0 S