Metamath Proof Explorer


Theorem subrgmcl

Description: A subring is closed under multiplication. (Contributed by Mario Carneiro, 2-Dec-2014) (Proof shortened by AV, 30-Mar-2025)

Ref Expression
Hypothesis subrgmcl.p ⊢ · ˙ = ⋅ R
Assertion subrgmcl ⊢ A ∈ SubRing ⁡ R ∧ X ∈ A ∧ Y ∈ A → X · ˙ Y ∈ A

Proof

Step Hyp Ref Expression
1 subrgmcl.p ⊢ · ˙ = ⋅ R
2 subrgsubrng ⊢ A ∈ SubRing ⁡ R → A ∈ SubRng ⁡ R
3 1 subrngmcl ⊢ A ∈ SubRng ⁡ R ∧ X ∈ A ∧ Y ∈ A → X · ˙ Y ∈ A
4 2 3 syl3an1 ⊢ A ∈ SubRing ⁡ R ∧ X ∈ A ∧ Y ∈ A → X · ˙ Y ∈ A