Metamath Proof Explorer


Theorem subrgring

Description: A subring is a ring. (Contributed by Stefan O'Rear, 27-Nov-2014)

Ref Expression
Hypothesis subrgring.1 ⊢ S = R ↾ 𝑠 A
Assertion subrgring ⊢ A ∈ SubRing ⁡ R → S ∈ Ring

Proof

Step Hyp Ref Expression
1 subrgring.1 ⊢ S = R ↾ 𝑠 A
2 eqid ⊢ Base R = Base R
3 eqid ⊢ 1 R = 1 R
4 2 3 issubrg ⊢ A ∈ SubRing ⁡ R ↔ R ∈ Ring ∧ R ↾ 𝑠 A ∈ Ring ∧ A ⊆ Base R ∧ 1 R ∈ A
5 4 simplbi ⊢ A ∈ SubRing ⁡ R → R ∈ Ring ∧ R ↾ 𝑠 A ∈ Ring
6 5 simprd ⊢ A ∈ SubRing ⁡ R → R ↾ 𝑠 A ∈ Ring
7 1 6 eqeltrid ⊢ A ∈ SubRing ⁡ R → S ∈ Ring