Metamath Proof Explorer


Theorem subrgsubg

Description: A subring is a subgroup. (Contributed by Mario Carneiro, 3-Dec-2014)

Ref Expression
Assertion subrgsubg ⊢ A ∈ SubRing ⁡ R → A ∈ SubGrp ⁡ R

Proof

Step Hyp Ref Expression
1 subrgrcl ⊢ A ∈ SubRing ⁡ R → R ∈ Ring
2 ringgrp ⊢ R ∈ Ring → R ∈ Grp
3 1 2 syl ⊢ A ∈ SubRing ⁡ R → R ∈ Grp
4 eqid ⊢ Base R = Base R
5 4 subrgss ⊢ A ∈ SubRing ⁡ R → A ⊆ Base R
6 eqid ⊢ R ↾ 𝑠 A = R ↾ 𝑠 A
7 6 subrgring ⊢ A ∈ SubRing ⁡ R → R ↾ 𝑠 A ∈ Ring
8 ringgrp ⊢ R ↾ 𝑠 A ∈ Ring → R ↾ 𝑠 A ∈ Grp
9 7 8 syl ⊢ A ∈ SubRing ⁡ R → R ↾ 𝑠 A ∈ Grp
10 4 issubg ⊢ A ∈ SubGrp ⁡ R ↔ R ∈ Grp ∧ A ⊆ Base R ∧ R ↾ 𝑠 A ∈ Grp
11 3 5 9 10 syl3anbrc ⊢ A ∈ SubRing ⁡ R → A ∈ SubGrp ⁡ R