Metamath Proof Explorer


Theorem subrngid

Description: Every non-unital ring is a subring of itself. (Contributed by AV, 14-Feb-2025)

Ref Expression
Hypothesis subrngss.1 B = Base R
Assertion subrngid R Rng B SubRng R

Proof

Step Hyp Ref Expression
1 subrngss.1 B = Base R
2 id R Rng R Rng
3 1 ressid R Rng R 𝑠 B = R
4 3 2 eqeltrd R Rng R 𝑠 B Rng
5 ssidd R Rng B B
6 1 issubrng B SubRng R R Rng R 𝑠 B Rng B B
7 2 4 5 6 syl3anbrc R Rng B SubRng R