Metamath Proof Explorer


Theorem subrngin

Description: The intersection of two subrings is a subring. (Contributed by AV, 15-Feb-2025)

Ref Expression
Assertion subrngin A SubRng R B SubRng R A B SubRng R

Proof

Step Hyp Ref Expression
1 intprg A SubRng R B SubRng R A B = A B
2 prssi A SubRng R B SubRng R A B SubRng R
3 prnzg A SubRng R A B
4 3 adantr A SubRng R B SubRng R A B
5 subrngint A B SubRng R A B A B SubRng R
6 2 4 5 syl2anc A SubRng R B SubRng R A B SubRng R
7 1 6 eqeltrrd A SubRng R B SubRng R A B SubRng R