Metamath Proof Explorer


Theorem symgfixfo

Description: The mapping of a permutation of a set fixing an element to a permutation of the set without the fixed element is an onto function. (Contributed by AV, 7-Jan-2019)

Ref Expression
Hypotheses symgfixf.p ⊢ P = Base SymGrp ⁡ N
symgfixf.q ⊢ Q = q ∈ P | q ⁡ K = K
symgfixf.s ⊢ S = Base SymGrp ⁡ N ∖ K
symgfixf.h ⊢ H = q ∈ Q ⟼ q ↾ N ∖ K
Assertion symgfixfo ⊢ N ∈ V ∧ K ∈ N → H : Q ⟶ onto S

Proof

Step Hyp Ref Expression
1 symgfixf.p ⊢ P = Base SymGrp ⁡ N
2 symgfixf.q ⊢ Q = q ∈ P | q ⁡ K = K
3 symgfixf.s ⊢ S = Base SymGrp ⁡ N ∖ K
4 symgfixf.h ⊢ H = q ∈ Q ⟼ q ↾ N ∖ K
5 1 2 3 4 symgfixf ⊢ K ∈ N → H : Q ⟶ S
6 5 adantl ⊢ N ∈ V ∧ K ∈ N → H : Q ⟶ S
7 eqeq1 ⊢ i = j → i = K ↔ j = K
8 fveq2 ⊢ i = j → s ⁡ i = s ⁡ j
9 7 8 ifbieq2d ⊢ i = j → if i = K K s ⁡ i = if j = K K s ⁡ j
10 9 cbvmptv ⊢ i ∈ N ⟼ if i = K K s ⁡ i = j ∈ N ⟼ if j = K K s ⁡ j
11 1 2 3 4 10 symgfixfolem1 ⊢ N ∈ V ∧ K ∈ N ∧ s ∈ S → i ∈ N ⟼ if i = K K s ⁡ i ∈ Q
12 11 3expa ⊢ N ∈ V ∧ K ∈ N ∧ s ∈ S → i ∈ N ⟼ if i = K K s ⁡ i ∈ Q
13 simpr ⊢ N ∈ V ∧ K ∈ N → K ∈ N
14 13 anim1i ⊢ N ∈ V ∧ K ∈ N ∧ s ∈ S → K ∈ N ∧ s ∈ S
15 14 adantl ⊢ p = i ∈ N ⟼ if i = K K s ⁡ i ∧ N ∈ V ∧ K ∈ N ∧ s ∈ S → K ∈ N ∧ s ∈ S
16 eqid ⊢ i ∈ N ⟼ if i = K K s ⁡ i = i ∈ N ⟼ if i = K K s ⁡ i
17 3 16 symgextres ⊢ K ∈ N ∧ s ∈ S → i ∈ N ⟼ if i = K K s ⁡ i ↾ N ∖ K = s
18 15 17 syl ⊢ p = i ∈ N ⟼ if i = K K s ⁡ i ∧ N ∈ V ∧ K ∈ N ∧ s ∈ S → i ∈ N ⟼ if i = K K s ⁡ i ↾ N ∖ K = s
19 18 eqcomd ⊢ p = i ∈ N ⟼ if i = K K s ⁡ i ∧ N ∈ V ∧ K ∈ N ∧ s ∈ S → s = i ∈ N ⟼ if i = K K s ⁡ i ↾ N ∖ K
20 reseq1 ⊢ p = i ∈ N ⟼ if i = K K s ⁡ i → p ↾ N ∖ K = i ∈ N ⟼ if i = K K s ⁡ i ↾ N ∖ K
21 20 eqeq2d ⊢ p = i ∈ N ⟼ if i = K K s ⁡ i → s = p ↾ N ∖ K ↔ s = i ∈ N ⟼ if i = K K s ⁡ i ↾ N ∖ K
22 21 adantr ⊢ p = i ∈ N ⟼ if i = K K s ⁡ i ∧ N ∈ V ∧ K ∈ N ∧ s ∈ S → s = p ↾ N ∖ K ↔ s = i ∈ N ⟼ if i = K K s ⁡ i ↾ N ∖ K
23 19 22 mpbird ⊢ p = i ∈ N ⟼ if i = K K s ⁡ i ∧ N ∈ V ∧ K ∈ N ∧ s ∈ S → s = p ↾ N ∖ K
24 23 ex ⊢ p = i ∈ N ⟼ if i = K K s ⁡ i → N ∈ V ∧ K ∈ N ∧ s ∈ S → s = p ↾ N ∖ K
25 24 adantl ⊢ N ∈ V ∧ K ∈ N ∧ s ∈ S ∧ p = i ∈ N ⟼ if i = K K s ⁡ i → N ∈ V ∧ K ∈ N ∧ s ∈ S → s = p ↾ N ∖ K
26 12 25 rspcimedv ⊢ N ∈ V ∧ K ∈ N ∧ s ∈ S → N ∈ V ∧ K ∈ N ∧ s ∈ S → ∃ p ∈ Q s = p ↾ N ∖ K
27 26 pm2.43i ⊢ N ∈ V ∧ K ∈ N ∧ s ∈ S → ∃ p ∈ Q s = p ↾ N ∖ K
28 4 fvtresfn ⊢ p ∈ Q → H ⁡ p = p ↾ N ∖ K
29 28 eqeq2d ⊢ p ∈ Q → s = H ⁡ p ↔ s = p ↾ N ∖ K
30 29 adantl ⊢ N ∈ V ∧ K ∈ N ∧ s ∈ S ∧ p ∈ Q → s = H ⁡ p ↔ s = p ↾ N ∖ K
31 30 rexbidva ⊢ N ∈ V ∧ K ∈ N ∧ s ∈ S → ∃ p ∈ Q s = H ⁡ p ↔ ∃ p ∈ Q s = p ↾ N ∖ K
32 27 31 mpbird ⊢ N ∈ V ∧ K ∈ N ∧ s ∈ S → ∃ p ∈ Q s = H ⁡ p
33 32 ralrimiva ⊢ N ∈ V ∧ K ∈ N → ∀ s ∈ S ∃ p ∈ Q s = H ⁡ p
34 dffo3 ⊢ H : Q ⟶ onto S ↔ H : Q ⟶ S ∧ ∀ s ∈ S ∃ p ∈ Q s = H ⁡ p
35 6 33 34 sylanbrc ⊢ N ∈ V ∧ K ∈ N → H : Q ⟶ onto S